grep for a particular pattern and remove 5 lines above the pattern and 6 lines below the pattern
root@server1 # cat filename
Shell Programming and Scripting test1
Shell Programminsada asda
dasd asd Shell Programming and Scripting Post New Thread
Shell Programming and S sadsa ... (17 Replies)
hi,,
i hav a file with many lines.i need to remove all lines before a line begginning with a specific pattern from the file because these lines are not required.
Can u help me out with either a perl script or shell script
example:-
if file initially contains lines:
a
b
c
d
.1.2
d
e
f... (2 Replies)
I need to remove all lines which does not match the pattern from a text file (batch of text files). I also need to keep the header line which is the first line of the file. Please can you provide an example for that.
I used this to solve half of my work. I was unable to keep the first line of... (3 Replies)
Hi,
I have requirement that I need to split my input file into two files based on a search pattern "abc"
For eg. my input file has below content
abc
defgh
zyx
I need file 1 with
abc
and file2 with
defgh
zyx
I can use grep command to acheive this. But with grep I need... (8 Replies)
Hi,
I have more than 30,000 records in a flat file. I want to remove footer from the file by searching a string pattern for the footer.
Example.... let the flat file test.dat contains below records.
record1
record2
record3
..
..
..
record31000
Total records 31000
I want to remove the... (6 Replies)
Not sure how I can accomplish this. I would like to remove all interfaces that have the commands I would like to see: switchport port-security, spanning-tree portfast. One line is no problem.
interface FastEthernet0/8
spanning-tree portfast
interface FastEthernet0/9
spanning-tree... (4 Replies)
Team,
I am trying to use sed to delete 15 lines, after pattern patch, which includes the pattern as well in Solaris. I used the below command, as we do it Linux, but it's not working as expected in Solaris.
I am getting the error as "garbled".sed '/\/table/,+15d' status.html
sed: command... (8 Replies)
In the awk below I am trying to remove all lines above and including the pattern Test or Test2. Each block is seperated by a newline and Test2 also appears in the lines to keep but it will always have additional text after it. The Test to remove will not. The awk executed until the || was added... (2 Replies)
Discussion started by: cmccabe
2 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)