03-20-2013
Quote:
Originally Posted by
Michael Stora
Do you mean that normal shell expansion (a subset of RegEx rules) works?
Shell expansion works in case statements, yes. But it's not a regex. It's not even a subset of regex... It
looks similar but acts very different.
* isn't a wildcard in regex, it's a modifier. "*" isn't a valid regex, but ".*" would be (where . is special character meaning 'any character').
BASH does have an operator for regex, but you're not using it.
This User Gave Thanks to Corona688 For This Post:
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hello.
Consider the following magic words:
# ls `which adduser`
ls: /usr/sbin/adduser: No such file or directory
#
Hmmm...
Then:
# ls /usr/sbin/adduser
/usr/sbin/adduser
#
Now what?
Unforunately this little sniippet is used in my debian woody server's mysql pre install script.... (2 Replies)
Discussion started by: osee
2 Replies
2. UNIX for Dummies Questions & Answers
Portion of my script below :
if ; then
NUMBEROFFEILDS=`cat ${BASE_SCRIPT_LOC}/standardfilecleanup.lst|grep -w ${db_file_path}|awk -F: '{print NF}'`
COUNT=4
while ; do
awk_var="$"`echo $COUNT`
file_name1=`cat ${BASE_SCRIPT_LOC}/standardfilecleanup.lst|grep -w... (1 Reply)
Discussion started by: findprakash
1 Replies
3. Shell Programming and Scripting
total=0
seq 1 5 | while read i ; do
total=$(($total+$i))
echo $total
done
echo $totalThis outputs:
1
3
6
10
15
0whereas I am expecting:
1
3
6
10
15
15My bash version: (4 Replies)
Discussion started by: meharo
4 Replies
4. Shell Programming and Scripting
I am trying to get folder names that contain only numbers.
Can someone explain why following command is printing 'total 450' as part of output..
$> ls -lt | awk '$9 ~ /^*$/' | more
total 450
drwxr-x--x 3 user1 group1 512 Mar 9 2008 329227163
drwxr-x--x 3 user1 group1 ... (17 Replies)
Discussion started by: kchinnam
17 Replies
5. Shell Programming and Scripting
for i in `cat /export/home/afahmed/Arrvial_time.txt`
do
echo $i
echo $i | awk '$3 < $D { print $4 }' >> dynamic_DF.txt;
done
When i echo, its echo as
Nov
15
02:24
/export/home/pp_adm/inbound//wwallet_20111115.txt where i expect it to be Nov 15 02:24... (7 Replies)
Discussion started by: afahmed
7 Replies
6. Shell Programming and Scripting
case "$freq" in
" Hz") low=250; high=550;;
"8 Hz") low=250; high=1000;;
" Hz") low=400; high=1000;;
"63 Hz") low=550; high=1000;;
" Hz") low=400; high=550;;
... (2 Replies)
Discussion started by: Michael Stora
2 Replies
7. Shell Programming and Scripting
Hi,
I have prepared a script and trying to execute it but not getting expected output. Could you please help and advise what is going wrong.
"If else" part in below script is not working basically.
I am running it on HP-UX.
for i in slpd puma sfmdb
do
echo "******\t$i\t*******"
echo... (10 Replies)
Discussion started by: sv0081493
10 Replies
8. UNIX for Advanced & Expert Users
I ran into the following and still do not understand entirely the rationale behind this. If someone could explain why things are as they are I'd be thankful.
The following was tested on AIX 7.1 with ksh88, but i suspect that to be ubiquitous. In an installation routine i had to create a set of... (6 Replies)
Discussion started by: bakunin
6 Replies
9. Shell Programming and Scripting
Below is what i have in my script.
htcount=$(curl -s --user tomcatstatus:tomcatstatus http://`hostname`.mypc.com:887/manager/jmxproxy?qry=Catalina:type=ThreadPool,name=\"http-nio-887\" |grep sBusy | cut -d ' ' -f2)
echo $htcount
if ; then
echo "more than 10"
else
echo "Less than 10"
fi... (6 Replies)
Discussion started by: mohtashims
6 Replies
10. Shell Programming and Scripting
I'm having an issue with bash read input when using a case statement.
The script halts and doesn't read the input on the first loop. if I hit enter then the scripts starts to respond as expected. Need some help here.
defaultans=8hrs
read -e -i $defaultans -p "${bldwht}How long would you like... (5 Replies)
Discussion started by: woodson2
5 Replies
LEARN ABOUT LINUX
re_exec
RE_COMP(3) Linux Programmer's Manual RE_COMP(3)
NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(char *regex);
int re_exec(char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO
regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
GNU
1995-07-14 RE_COMP(3)