Hi Don,
Yeah, I just realized (and figured out one fallacy) that I need to pass it like
Code:
if ["$jobNo" == Null -a "$jobNo1" != Null ]; then
do something with jobNo1
elif ["$jobNo" != Null -a "$jobNo1" == Null ]; then
do something with jobNo
elif ["$jobNo" == Null -a "$jobNo1" == Null ]; then
echo "BOTH NULL, existing "
elif ["$jobNo" != Null -a "$jobNo1" == Null]; then
do something with both $jobNo,$jobNo1
Can you help me in passing these as elif ["$jobNo" != Null -a "$jobNo1" == Null]; ?
Will it work elif ["$jobNo" != "" -a "$jobNo1" == ""]; ??
Also, in the previous script, it was never passing the "do someting" for both
string as NULL command. So I assumed that I did pass them correctly.
Thanks
emily
No! No! No! No! No! No!
First, none of your awk scripts print the string "Null", so comparing the output produced by one of your awk scripts to the string Null is a waste of time; no matter what your input files contain, you already know what the result of the comparison will be.
Second, there has to be a space after the [ and before the ] in:
Code:
if [ expression ]
Third, although some shells may accept it as an extension to the standards, there is no == binary string comparison primitive for the test or [ commands.
And fourth, you don't have a fi to terminate your if statement.
I'm guessing that you want something more like:
Code:
if [ "$jobNo" = "" -a "$jobNo1" != "" ]; then
printf "Job(s) cancelled: %s\n" "$jobNo1"
elif [ "$jobNo" != "" -a "$jobNo1" = "" ]; then
printf "Job(s) with non-zero wrapper exit status: %s\n" "$jobNo"
elif [ "$jobNo" = "" -a "$jobNo1" = "" ]; then
echo "No jobs with non-zero wrapper exit status and no jobs cancelled."
elif [ "$jobNo" != "" -a "$jobNo1" != "" ]; then
printf "Job(s) with non-zero wrapper exit status: %s\n" "$jobNo"
printf "Job(s) cancelled: %s\n" "$jobNo1"
fi
or, equivalently:
Code:
if [ -z "$jobNo" -a -n "$jobNo1" ]; then
printf "Job(s) cancelled: %s\n" "$jobNo1"
elif [ -n "$jobNo" -a -z "$jobNo1" ]; then
printf "Job(s) with non-zero wrapper exit status: %s\n" "$jobNo"
elif [ -z "$jobNo" -a -n "$jobNo1" ]; then
echo "No jobs with non-zero wrapper exit status and no jobs cancelled."
else printf "Job(s) with non-zero wrapper exit status: %s\n" "$jobNo"
printf "Job(s) cancelled: %s\n" "$jobNo1"
fi
or:
Code:
if [ ! "$jobNo" ] && [ "$jobNo1" ]; then
printf "Job(s) cancelled: %s\n" "$jobNo1"
elif [ "$jobNo" ] && [ ! "$jobNo1" ]; then
printf "Job(s) with non-zero wrapper exit status: %s\n" "$jobNo"
elif [ ! "$jobNo" ] && [ ! "$jobNo1" ]; then
echo "No jobs with non-zero wrapper exit status and no jobs cancelled."
else printf "Job(s) with non-zero wrapper exit status: %s\n" "$jobNo"
printf "Job(s) cancelled: %s\n" "$jobNo1"
fi
Obviously you'll want to replace the printf and echo statements with the processing you want to perform, but this gives you three equivalent runnable sequences of commands that will verify that you have correctly adjusted the logic in your if statement tests.
This User Gave Thanks to Don Cragun For This Post:
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