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Top Forums Shell Programming and Scripting Dealing with white spaces in bash scripts Post 302781589 by venmx on Sunday 17th of March 2013 07:40:12 AM
Old 03-17-2013
Quote:
If you only need to support GNU tools (I'm making the assumption that you're using GNU find), a simpler, more efficient solution presents itself:
Thanks alister! I'm learning something every day Smilie

So, your doing away with awk by using -printf option to format the output of find, then using read to set the variables that can be used by chgrp. Very nice.

But can you believe people actually have file/directory names of Windows paths?! And URL's and even ones with line breaks built-in! Special characters and spaces galore... amazing!

In the end, I had to set/reset the IFS variable and multiple sed substitution to bring most of them in line. But not all! I'm bored of it now, so I'll send the few offending names to their respective users to fix themselves.

Code:
#!/bin/sh

SAVEIFS=$IFS
IFS=$(echo -en "\n\b")

find /home -gid 200 \( -type f -o -type d -o -type l \) | sed -e 's/\\/\\\\/g;s/:/\\:/g;s/ /\\ /g;s/\n//g' |
while read i; do
  chgrp -vh `ls -lnd "${i}" | awk '{print $3}'` "${i}"
#  ls -lnd "${i}"
done

IFS=$SAVEIFS

Messy Smilie
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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