how to add 2 float values to each other?
i tried this and it doesnt work:
#!bin/bash
numone=1.234
numtwo=0.124
total=`expr $numone + $numtwo`
echo $total
thanks (5 Replies)
Hello, I have a file, and one column has both positive and negative numbers. Does anyone know how I can calculate the total of all the values (i.e, +ve and -ve).
eg:
col1 col2 col3
data 23 data
data 76 data
data -30 data
Thanks
Khoom (1 Reply)
Hi this is quite a simple question... I am new to LINUX/UNIX and so I am just trying to create a very basic program. The idea is that when the user runs the program (from the shell) they enter 3 values and the program will add them up:
"./sum 23 5 1
29"
my code for this program is as follows:
... (4 Replies)
Hi All,
I have a file example.csv which looks like this
GrpID,TargetID,Signal,Avg_Num
CSCH74_1_1,2007,61,256
CSCH74_1_1,212007,647,679
CSCH74_1_1,12007,3,32
CSCH74_1_1,207,299,777
I want the output as
GrpID,TragetID,Signal-CSCH74_1_1,Avg_Num
CSCH74_1_1,2007,61,256... (4 Replies)
Hi
I figured how to add my list of numbers. However how do I count so that after a certain number it lists the line.
Example:
12 test1
46 test2
195 test3
174 test4
634 test5
185 test6
94 test7
So basically add the numbers and when the addition reaches 300 or less
print the... (8 Replies)
I am writing a bash script on ubuntu11.10
I have some string having numbers and letter and want to add all the numbers together
For example
1s2d23f
I want to perform
1 + 2 + 23 and store it in a variable (3 Replies)
I have a file which has following contents which I want to add up.
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
28170.24
139038.72
139038.72
139038.72
139038.72 (5 Replies)
Hi,
I would like to add a new column containing the row numbers to a text file. How do I go about doing that? Thanks!
Example input:
A X
B Y
C D
Output:
A X 1
B Y 2
C D 3 (5 Replies)
Hi again. Sorry for all the questions — I've tried to do all this myself but I'm just not good enough yet, and the help I've received so far from bartus11 has been absolutely invaluable. Hopefully this will be the last bit of file manipulation I need to do.
I have a file which is formatted as... (4 Replies)
Discussion started by: crunchgargoyle
4 Replies
LEARN ABOUT CENTOS
mrtg-logfile
MRTG-LOGFILE(1) mrtg MRTG-LOGFILE(1)NAME
mrtg-logfile - description of the mrtg-2 logfile format
SYNOPSIS
This document provides a description of the contents of the mrtg-2 logfile.
OVERVIEW
The logfile consists of two main sections.
The first Line
It stores the traffic counters from the most recent run of mrtg.
The rest of the File
Stores past traffic rate averates and maxima at increassing intervals.
The first number on each line is a unix time stamp. It represents the number of seconds since 1970.
DETAILS
The first Line
The first line has 3 numbers which are:
A (1st column)
A timestamp of when MRTG last ran for this interface. The timestamp is the number of non-skip seconds passed since the standard UNIX
"epoch" of midnight on 1st of January 1970 GMT.
B (2nd column)
The "incoming bytes counter" value.
C (3rd column)
The "outgoing bytes counter" value.
The rest of the File
The second and remaining lines of the file contains 5 numbers which are:
A (1st column)
The Unix timestamp for the point in time the data on this line is relevant. Note that the interval between timestamps increases as you
progress through the file. At first it is 5 minutes and at the end it is one day between two lines.
This timestamp may be converted in OpenOffice Calc or MS Excel by using the following formula
=(x+y)/86400+DATE(1970;1;1)
(instead of ";" it may be that you have to use "," this depends on the context and your locale settings)
you can also ask perl to help by typing
perl -e 'print scalar localtime(x),"
"'
x is the unix timestamp and y is the offset in seconds from UTC. (Perl knows y).
B (2nd column)
The average incoming transfer rate in bytes per second. This is valid for the time between the A value of the current line and the A
value of the previous line.
C (3rd column)
The average outgoing transfer rate in bytes per second since the previous measurement.
D (4th column)
The maximum incoming transfer rate in bytes per second for the current interval. This is calculated from all the updates which have
occured in the current interval. If the current interval is 1 hour, and updates have occured every 5 minutes, it will be the biggest 5
minute transfer rate seen during the hour.
E (5th column)
The maximum outgoing transfer rate in bytes per second for the current interval.
AUTHOR
Butch Kemper <kemper@bihs.net> and Tobias Oetiker <tobi@oetiker.ch>
2.17.4 2012-01-12 MRTG-LOGFILE(1)