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Top Forums Shell Programming and Scripting sed command to print first instance of pattern in range Post 302769235 by kg_gaurav on Monday 11th of February 2013 03:50:13 PM
Old 02-11-2013
using for n grep

I'm nt cmfortable wid sed. Bt i thunk it can be done using for loop n grep. As i'm posting through mobile so code isn't testd. Plz modify to meet ur need
Code:
for $ln `cat testfile.txt`
{
  num=echo $ln | grep -Po *[0-9]{2}
 if [ $num = '10' ]
 echo $ln
exit 0
fi
}


it'll search upto first occurance n then exit. Plz revrt incase of furthr explanation

Last edited by Franklin52; 02-13-2013 at 05:13 AM.. Reason: Please use code tags for data and code samples
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep is used to invoke the grep on compress'ed or gzip'ed files. All options specified are passed directly to grep. If no file is speci- fied, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If zgrep is invoked as zegrep or zfgrep then egrep or fgrep is used instead of grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. For example: for sh: GREP=fgrep zgrep string files for csh: (setenv GREP fgrep; zgrep string files) AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), egrep(1), fgrep(1), zdiff(1), zmore(1), znew(1), zforce(1), gzip(1), gzexe(1) ZGREP(1)
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