awk to print first row with forth column and last row with fifth column in each file
file with this content
Quote:
PPP11 OFS HIGH 1200 1401 + 0 KNOW
PPP22 OFS HIGH 1433 1588 - 2 KNOW
Quote:
u want to print first row with fourth column and second row with fifth column; the code is below
The error is shown with syntax error; what can be done
Quote:
And another question is that if there is to print first row with fourth column and last row with fifth column; in each file; how the solution with awk will be?
Hi,
I want to write a shell script which increments a particular column in a row from a text file and then adds another row below the current row with the incremented value .
For Eg .
if the input file has a row :
abc xyz lmn 89 lm nk o p
I would like the script to create something like... (9 Replies)
Hello,
I have an input file like the following:
11_3_4
2_1_35
3_15__
_16989
Where '_' is a space. The data is in a table. Is there a way for the program to prompt the user for x1,y1 and x2,y2, where x1,y1 is the desired number (for example x=6 y=4 is a value of 4) and move to a desired spot... (2 Replies)
Hi, Please read the whole thread.
I have been working on this script below. It works fine, feel free to copy and test with the INPUT File below as well.
example:
PACKET DATA PROTOCOL CONTEXT DATA
APNID PDPADD EQOSID VPAA PDPCH PDPTY PDPID
10 ... (6 Replies)
Hi Friends,
I have a single column data like below.
1
2
3
4
5
I need the output like below.
0
1
2
3
4
where each row (including first row) subtracting from first row and the result should print below like the way shown in output file.
Thanks
Sid (11 Replies)
Hi all
I have file with columns
F3 pathway CPS
F2
H2
H4
H5
H6 no pathway CMP
H7
H8
H9
H10
My expected output is
F3 pathway CPS
F2 pathway CPS (10 Replies)
I have a table with this structure:
cola colb colc
1 19 lemon
20 31 lemon
32 100 lemon
159 205 cherries
210 500 cherries
and need to parse it into this format:
cola colb colc
1 100 lemon
159 500 cherries
So I need the first row of cola and the last row of colb if colc has the... (3 Replies)
Hi,
I have a comma separated file. I would like to print every alternate columns into a new row.
Example input file:
Name : John, Age : 30, DOB : 30-Oct-2018
Example output:
Name,Age,DOB
John,30,30-Oct-2018 (3 Replies)