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Full Discussion: Looking out for the file-watcher
Top Forums Shell Programming and Scripting Looking out for the file-watcher Post 302764641 by tush on Thursday 31st of January 2013 05:18:41 PM
Old 01-31-2013
Question Looking out for the file-watcher
Hi friends,

I do not have much thoughts so need any help on the below issue:

I need to create shell script that will find the files & throw an error through job (autosys) when file not found.
Daily we use to receive 3 files from a system.

Obstacles:

1) All 3 files names are same.
2) Timestamp is same.
3) Even the received time may be same
Thats why got stuck.
Script which I have created:

Code:
first_time_stamp=`ls -l/apps/rdp/prd/prd1/interfaces/auto/input/archive/*tri003_global*20130131* | awk '{print $8}' | sed -n '1p'`
sec_time_stamp=`ls -l /apps/rdp/prd/prd1/interfaces/auto/input/archive/*tri003_global*20130131* | awk '{print $8}' | sed -n '2p'`
third_time_stamp=`ls -l /apps/rdp/prd/prd1/interfaces/auto/input/archive/*tri003_global*20130131* | awk '{print $8}' | sed -n '3p'`

if[ $first_time_stamp -eq $sec_time_stamp ]; then
echo "Two files received at the same time"
elif [ $first_time_stamp -gt $sec_time_stamp && $third_time_stamp -gt $sec_time_stamp ]; then
echo "Three files reveived & time stamp's are different"
else
echo files are missing"
fi

My inner feeling is that the above script is not good to solve my pupose.

Script should be give this:

Code:
[first file not arrived]; then
contact upstream for the first file
[second file not arrived] then
contact upstream for the second file
[third file not arrived] then
contact upstream for the third file
else
echo "All looks good & all 3 files arrived"

Sample file name:

Code:
-rw-rw-r-- 1 32598 wmadmin 157335 Jan 31 13:10 tri003_global_201301310810_erd.txt-20130131131318
-rw-rw-r-- 1 32598 wmadmin 157334 Jan 31 15:31 tri003_global_201301311030_erd.txt-20130131153255
-rw-rw-r-- 1 32598 wmadmin 157368 Jan 31 18:24 tri003_global_201301311324_erd.txt-20130131182819

Really appreciate if someone can help me out here.

Thanks very much
Last edited by DukeNuke2; 01-31-2013 at 06:34 PM.. Reason: Code tags
 

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LEARN ABOUT OSF1

uudemon.cleanu

uudemon(4)						     Kernel Interfaces Manual							uudemon(4)

NAME

       uudemon.admin,  uudemon.cleanu,	uudemon.hour,  uudemon.poll  -	Administrative shell scripts for polling remote systems, cleaning up spool
       directories, reporting status to the system administrator, and routine invocations of the uuxqt and uusched daemons

SYNOPSIS

       These shell scripts reside in the following directory:
	  /usr/lib/uucp

DESCRIPTION

       All the scripts can be run from the command line or can be run automatically by the cron daemon. To automatically run the  scripts,  remove
       the comment character (#) from the beginning of the relevant line in the /var/spool/cron/crontabs/uucp file.

       This  script  reports  status  to  the system administrator. It issues the uustat command to find out the status of uucp jobs. It mails the
       results to the uucp login ID. The script may be modified to send mail to any login ID such as the uucp administrative login ID  (uucpa)	or
       root.  This script cleans up the /var/spool/uucp and /var/spool/uucppublic directories by running the uucleanup command. The uucleanup com-
       mand is run with the following parameters: -C7, -D7, X2, -o2, -W1.  This script runs the uusched and uuxqt daemons in the background.  This
       script  polls  the  systems  listed  in	the  /usr/lib/uucp/Poll file.  The uudemon.poll script should be scheduled before the uudemon.hour
       script. This allows uudemon.poll to create any command files before cron runs the uudemon.hour script.

FILES

       Contains the uudemon.admin, uudemon.cleanu, uudemon.hour and uudemon.poll files.  Contains the uucp file.

RELATED INFORMATION

       Commands: cron(8), uucleanup(8), uusched(8), uuxqt(1)

       Files: /usr/lib/uucp delim off

																	uudemon(4)
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