I have a file with 100s of lines of text. I want to perform an extraction of this line:
I have not been able to extract it. Should I try expr match or is there another method? This line has data both in front of and in back of it. I do not have grep -o as an option on my system. Any ideas are greatly appreciated.
I'm executing "wc -lc" command in a c shell script to get record count and byte counts and writing them to a file. I get the result with the full pathname of the file. But I do not want the path name to be printed in the output file. I heard that using Awk we can get this but I don't have any... (4 Replies)
Hi,
I want to extract a part of filename and pass it as a parameter to one of the scripts. Could someone help.
File name:-
NLL_NAM_XXXXX.XXXXXXX_1_1.txt.
Here i have to extract only XXXXX.XXXXXXX and the position will be constant. that means that i have to extract some n characters from... (6 Replies)
Hi All,
I am trying to write a small shell programming to get db2 database size info. The command I am going to use is- db2 "CALL GET_DBSIZE_INFO(?, ?, ?, -1)"
and the output of above command generally is-
Value of output parameters
--------------------------
Parameter Name :... (4 Replies)
Hi friends,
I want to select and use the certain part of a line. For example I have the following line
home/1245/hgdf/acsdf/myhome/afolder/H2O/endfile
how can I extract the part " /myhome/afolder/H2O/endfile "
thanks (6 Replies)
Hi,
I have the following string and I need to extract the date from it:
TextHere,2012/07/11,1
I tried using sed:
sed -n 's#^.*\({4}/{2}/{2}\).*$#\1#p'
But it doesn't return anything. The following line doesn't even return '2012':
sed -n 's/^.*\({4}\).*$/\1/p'
I used to use grep -o... (6 Replies)
I have to extract number part (Date and timestamp part ) from the following 3 strings
AB_XYZA_20130930183017.log
AB_DY_XYZA_20130930183017.log
AB_GZU_20130930183017.log
Output should be
20130930183017
Please help me to get the string like above
Thanks (2 Replies)
Hi,
I have a string with name as 20140412-s1-Potopolive_promos_20140412. So I want to extract only Potopolive string. Could you please help me the command.
O/p : Potopolive
Thx in advance (5 Replies)
Hi All,
Let us say we have 5 log files, extract the data from all log files and save the output in a file.
home/log/first.log
home/log/second.log
home/log/third.log
home/log/four.log
home/log/five.log
I want to extract the following text from the log files and save the output in a file.... (7 Replies)
Discussion started by: ROCK_PLSQL
7 Replies
LEARN ABOUT PLAN9
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)