Hi,
I know there is a Q/A section and lots of posts regarding date command here. I am sorry to start a new thread. I am very new to shell scripting (actually i am working on my first program), so please forgive my ignorance. I could not find an answer to my problem else where so i posted it... (10 Replies)
Hi,
Is there any way to change one date format to another ?? I mean I have a file having dates in the format (Thu Sep 29 2005) ... and i wud like to change these to YYYYMMDD format .. is there any command which does so ?? Or anything like enum which we have in C ??
Thanks in advance,
... (5 Replies)
Hi,
There are lots of threads about how to manipulate the date using date +%m %.......
But how can I change the default format of the commad date?
$ date
Mon Apr 10 10:57:15 BST 2006
This would be on fedora and SunOs.
Cheers,
Neil (4 Replies)
Discussion started by: nhatch
4 Replies
4. Post Here to Contact Site Administrators and Moderators
In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.
Thanks. (1 Reply)
Hi, I have a column in a table of Timestamp datatype. For Example : Var1 is the column 2008-06-26-10.10.30.2006. I have Given query as date(var1) and time (var1) I got the file as in the below format :
File1:
Col1 Col2
2008-06-02|12.36.06
2008-06-01|23.36.35
But the problem is... (7 Replies)
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
Hi All,
I am new to this forum, could any one help me out in resolving the below issue.
Input of the flat file contains several lines of text for example find below:
5022090,2,4,7154,88,,,,,4/1/2011 0:00,Z,L,2
5022090,3,1,6648,88,,,,,4/1/2011 0:00,Z,,1
5022090,4,1,6648,88,,,,,4/1/2011... (0 Replies)
Hi all,
I have a file with below data
af23b|11-FEB-12|acc7
ad23b|12-JAN-12|acc4
as23b|15-DEC-11|acc5
z123b|18-FEB-12|acc1
I need the output as below:-(date in yyyymmdd format)
af23b|20120211|acc7
ad23b|20120112|acc4
as23b|20111215|acc5
z123b|20120218|acc1
Please help me on this.... (7 Replies)
How can i make the date command output yesterday's date, current date and the date 4 days ago, in the following format:
2012-10-03
code:
date +% ???? (3 Replies)
Discussion started by: SkySmart
3 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)