Awk-sed help : to remove first and last line with pattern match: Post: 302759567

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Hi How Are you? I am doing fine! I need to go now? I will see you tomorrow! Basically I need to replace the entire line containing "doing" with a blank line: I need to the following output: Hi How Are you? I need to go now? I will see you tomorrow! Thanks in advance....

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awk with sed to combine lines and remove specific odd # pattern from line

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LEARN ABOUT MINIX

zgrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)

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sed - Replace Line which contains the Pattern match with a new line

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I need to know how to replace a line after a pattern match with an empty line using SED

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