I am trying to make a calculator. The user Enters number 1, chooses and operation, enters number 2, then chooses another operation or for the answer to be displayed.
eg. 1 + 1 = or 1 + 1 + 2 + 1 =
Both of these should be possible.
Code:
#!/bin/bash
read -p "what's the first number? " n1
PS3="what's the operation? "
select ans in add subtract multiply divide equals; do
case $ans in
add) op='+' ; break ;;
subtract) op='-' ; break ;;
multiply) op='*' ; break ;;
divide) op='/' ; break ;;
*) echo "invalid response" ;;
esac
done
read -p "what's the second number? " n2
ans=$(echo "$n1 $op $n2" | bc -l)
printf "%s %s %s = %s\n\n" "$n1" "$op" "$n2" "$ans"
exit 0
This is what I have written so far, but i cannot work out how to make it possible to let the user choose 'equals' or to loop back round to enter another operation. Any ideas what I can do to my code here? I have been stuck on this all day.
I dont want the user to enter the equation themselves, i want them to be choosing from a list.
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Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
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Discussion started by: wisecracker
2 Replies
LEARN ABOUT OSF1
rpmatch
rpmatch(3) Library Functions Manual rpmatch(3)NAME
rpmatch - Determines whether a response is affirmative or negative
LIBRARY
Standard C Library (libc.a)
SYNOPSIS
#include <stdlib.h>
int rpmatch( const char *response);
PARAMETERS
User input entered in response to a question that requires an affirmative or negative answer.
DESCRIPTION
The rpmatch() function determines whether the string value of the response parameter matches the affirmative or negative response expres-
sion as specified by the LC_MESSAGES category in the program's current locale. Both response expressions, defined in the locale, may be
extended regular expressions.
A possible value of the affirmative expression, yesexpr, for a English-language locale is "^([yY]|[yY][eE][sS])". This expression will
match any value of the response parameter that has consists of the letter Y (in uppercase or lowercase) or the letters YES (in any mixture
of uppercase and lowercase letters).
EXAMPLES
The following example requests a response from the user and uses the rpmatch() function to determine if the response is affirmative or neg-
ative.
#include <stdlib.h> #include <stdio.h> #include <locale.h> #include <string.h> #define SLENGTH 80
main() {
char str[SLENGTH], *eol;
int ans;
(void)setlocale(LC_ALL, "");
printf("Do you want to perform this operation: ");
fgets(str, SLENGTH, stdin);
if ((eol = strchr(str, '
')) != NULL)
*eol = '