Hey,
This is probably going to sound like an immensely stupid and dull question, but can someone please tell me whether the forward slash on the web address (http://) signifies that it is running on UNIX?
hanks (1 Reply)
Substituting the / for the \ I came up with this:
sed s/\\\\usr\\\\qm/\\\\\\\\qmi/g
Can anyone explain to me please, why I have to pass the slash four times?
:confused: (2 Replies)
Hi everyone! :)
I've been asked to write an article breaking down the basics of UNIX password information etc., and I've come across something in which I cannot find a definition for within Google.
Very simply, can anyone tell me what the difference is between a standard UNIX password, and... (4 Replies)
hi all,
im trying to use a sed command to remove all occurenes of \p\g
what i used so far is : sed 's!\p\g!!g' file
but this doesnt work ?
Any ideas, thanks for helping. (2 Replies)
Need help in finding pattern then replacing pattern that contains multiple
slashes ..
ex .
<imgp src="Attention_web.eps.jpg" align="left">
<imgp src="NewToday062308.eps.jpg">
replace with
<imgp src="/ww2/adpay/liner/Attention_web.eps.jpg" align="left">
<imgp... (2 Replies)
I know you can remove trialing slashes using:
#echo "/tmp/one/two/three////" | sed "s,/$,,"
/tmp/one/two/three///
But I want to know how to make it remove all trialing flashes in the front, and in the start, so the end result is:
tmp/one/two/three
Anyone have any idea how to do this... (6 Replies)
I'm trying to replace an alias with its match using sed but the match contains forward slashs so it causes the sed command to throw a garbled message..
cmd_list.txt sample
AIX_myserver_1011_vintella.sudoers_cmndalias sample
I'm trying to use the below but like I say it throws a... (5 Replies)
I have got the following contents and please can you advise me on how to extract the following data that appears between the very first slashes.
Thanks
i.e 576 , 10000, 1299
3/576/GPP///////NONE/0
50/10000/GPP///D4////GPP/0
234/1299/GPP///////NONE/0 (3 Replies)
I want to print 4052 slashes using this C program.
#include <stdio.h>
void main()
{
int i;
for (i=0; i<4052; i++)
printf ("/");
}
When i compile this via gcc am getting this error :
http://gyazo.com/e0403e4789575d181d1695f9db3e6d6e.png
Can anyone point out what am doing wrong? (15 Replies)
Discussion started by: vish6251
15 Replies
LEARN ABOUT DEBIAN
yaz-url
YAZ-URL(1) Commands YAZ-URL(1)NAME
yaz-url - YAZ URL fetch utility
SYNOPSIS
yaz-url [-H name:value] [-m method] [-O fname] [-p fname] [-u user/password] [-x proxy] [url...]
DESCRIPTION
yaz-url is utility to get web content. It is very limited in functionality compared to programs such as curl, wget.
The options must be precede the URL given on the command line to take effect.
Fetched HTTP content is written to stdout, unless option -O is given.
OPTIONS -H name:value
Specifies HTTP header content with name and value. This option can be given multiple times (for different names, of course).
-m method
Specifies the HTTP method to be used for the next URL. Default is method "GET". However, option -p sets it to "POST".
-O fname
Sets output filename for HTTP content.
-p fname
Sets a file to be POSTed in the folloing URL.
-u user/password
Specifies a user and a password to be uesd in HTTP basic authentication in the following URL fetch. The user and password must be
separated by a slash (this it is not possible to specify a user with a slash in it).
-x proxy
Specifies a proxy to be used for URL fetch.
SEE ALSO yaz(7)YAZ 4.2.30 04/16/2012 YAZ-URL(1)