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Shell Programming and Scripting
Grep problem
Post 302751821 by Yoda on Friday 4th of January 2013 02:15:52 PM
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Hi
I would like to know wheather there is anyway to pass a variable to grep argument like this
grep "$myvar" $myfile
i would put this in a function and then call this function by setting different values to myvar and myfile.
is this possible at all.
regards
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LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1) NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)