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Top Forums Shell Programming and Scripting Need help placing row below next to row above Post 302738585 by Don Cragun on Sunday 2nd of December 2012 04:24:14 AM
Old 12-02-2012
With the given input file, ripat's suggestion works fine. But using user supplied data as a format string to printf is risky. If an input line ever happens to contain a % character followed by an alphabetic character (with an optional string of digits before the alphabetic character), you could get very different results.
An alternative way to do this (avoiding this issue) is:
Code:
awk 'NR%6<2{print}NR%6>1{printf("%s",$0)}' output.txt

 

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ODBC_FETCH_ROW(3)							 1							 ODBC_FETCH_ROW(3)

odbc_fetch_row - Fetch a row

SYNOPSIS
bool odbc_fetch_row (resource $result_id, [int $row_number]) DESCRIPTION
Fetches a row of the data that was returned by odbc_do(3) or odbc_exec(3). After odbc_fetch_row(3) is called, the fields of that row can be accessed with odbc_result(3). PARAMETERS
o $result_id - The result identifier. o $row_number - If $row_number is not specified, odbc_fetch_row(3) will try to fetch the next row in the result set. Calls to odbc_fetch_row(3) with and without $row_number can be mixed. To step through the result more than once, you can call odbc_fetch_row(3) with $row_number 1, and then continue doing odbc_fetch_row(3) without $row_number to review the result. If a driver doesn't support fetching rows by number, the $row_number parameter is ignored. RETURN VALUES
Returns TRUE if there was a row, FALSE otherwise. PHP Documentation Group ODBC_FETCH_ROW(3)
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