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Top Forums Shell Programming and Scripting Need help placing row below next to row above Post 302738581 by sidiqmk on Sunday 2nd of December 2012 03:58:32 AM
Old 12-02-2012
Many thanks!
 

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IFX_FETCH_ROW(3)							 1							  IFX_FETCH_ROW(3)

ifx_fetch_row - Get row as an associative array

SYNOPSIS
array ifx_fetch_row (resource $result_id, [mixed $position]) DESCRIPTION
Fetches one row of data from the result associated with the specified result identifier. Subsequent calls to ifx_fetch_row(3) would return the next row in the result set, or FALSE if there are no more rows. PARAMETERS
o $result_id -$result_id is a valid resultid returned by ifx_query(3) or ifx_prepare(3) (select type queries only!). o $position - An optional parameter for a "fetch" operation on "scroll" cursors: NEXT, PREVIOUS, CURRENT, FIRST, LAST or a number. If you specify a number, an "absolute" row fetch is executed. This parameter is optional, and only valid for SCROLL cursors. RETURN VALUES
Returns an associative array that corresponds to the fetched row, or FALSE if there are no more rows. Blob columns are returned as integer blob id values for use in ifx_get_blob(3) unless you have used ifx_textasvarchar(1) or ifx_byteasvar- char(1), in which case blobs are returned as string values. EXAMPLES
Example #1 Informix fetch rows <?php $rid = ifx_prepare ("select * from emp where name like " . $name, $connid, IFX_SCROLL); if (! $rid) { /* ... error ... */ } $rowcount = ifx_affected_rows($rid); if ($rowcount > 1000) { printf ("Too many rows in result set (%d) <br />", $rowcount); die ("Please restrict your query<br /> "); } if (! ifx_do ($rid)) { /* ... error ... */ } $row = ifx_fetch_row ($rid, "NEXT"); while (is_array($row)) { for (reset($row); $fieldname=key($row); next($row)) { $fieldvalue = $row[$fieldname]; printf ("%s = %s,", $fieldname, $fieldvalue); } printf(" <br />"); $row = ifx_fetch_row($rid, "NEXT"); } ifx_free_result ($rid); ?> PHP Documentation Group IFX_FETCH_ROW(3)
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