Hi frnds :)
I need a small help...
I have a very long file containing 20 digits decimal number which i want to convert into the corresponding 16 digit hexadecimal values.
File looks like....
11908486672755551741
05446378739602232559
04862605079740156652
.
.
.
I tried the script
for i... (7 Replies)
hi ,
i need a script to convert number into hexadecimal base
for example: 237=>ED
it s very important for me thank you in advance for you help (5 Replies)
Hi all,
I have a small script to convert my HexaDecimal Input to Decimal as output.
#!/bin/ksh
hd=00208060
dec=`printf %d $hd`
echo $dec
Output of the above program:
printf: 00208060 not completely converted
16
But my expected output is "2130016".
How can i acheive this.
I... (2 Replies)
Hi,
Here is my script to read a file into array:
awk -F '+' '
# load first file into array indexed by fields 1 and 2
NR == FNR {
file1nr = FNR
for (i=3; i<NF; i++) {
file1 = $i
}
I have this... (5 Replies)
I have a text file of alphanumeric values listed one by one. I have to convert them to hexadecimal equivalents for each character seperated by ":" in Unix bash shell script. For example, 12345678 has to be converted to 31:32:33:34:35:36:37:38 (10 Replies)
I have searched and the answers I have found thus far have led me to this point, so I feel I am just about there.
I am trying to convert a column of hexadecimal to decimal values so that I can filter out via grep just the data I want. I was able to pull my original 3 character hex value and... (10 Replies)
Hi,
I want to convert two hexadecimal numbers to decimal using unix command line.
1cce446295197a9d6352f9f223a9b698
fc8f99ac06e88c4faf669cf366f60d
I tried using
`echo "ibase=16; $no |bc`
printf '%x\n' "1cce446295197a9d6352f9f223a9b698"
but it doesn't work for such big number it... (4 Replies)
Hi ,
seq can be 0...128
int windex = seq / 8;
int bindex = seq % 8;
unsigned char bitvalue = '\x01' << (7-bindex) ;
bpv.bitmapvalue = bitvalue;
This is the part of a program to convert decimal to bitmap value of hexadecimal.
I want this to change to convert only to... (1 Reply)
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)