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Top Forums Shell Programming and Scripting How to obtain a day of the week from the date? Post 302737081 by elixir_sinari on Wednesday 28th of November 2012 10:55:52 AM
Old 11-28-2012
Code:
perl -MPOSIX=mktime -e '@wday=qw(Sun Mon Tue Wed Thu Fri Sat);
$ARGV[0] =~ /(....)(..)(..)/;
print $wday[(localtime mktime(0,0,0,$3,$2-1,$1-1900))[6]],"\n"' YYYYMMDD

Replace YYYYMMDD with your date.
 

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POSIX::strptime(3pm)					User Contributed Perl Documentation				      POSIX::strptime(3pm)

NAME
POSIX::strptime - Perl extension to the POSIX date parsing strptime(3) function SYNOPSIS
($sec, $min, $hour, $mday, $mon, $year, $wday, $yday) = POSIX::strptime("string", "Format"); DESCRIPTION
Perl interface to strptime(3) FUNCTIONS
strptime ($sec, $min, $hour, $mday, $mon, $year, $wday, $yday) = POSIX::strptime(string, format); The result for any value not extracted is not defined. Some platforms may reliably return "undef", but this is dependent on the strptime(3) function in the underlying C library. For example, only the following fields may be relied upon: my ($min, $hour) = ( POSIX::strptime( "01:23", '%H:%M' ) )[1,2]; my ($mday, $mon, $year) = ( POSIX::strptime( "2010/07/16", '%Y/%m/%d' ) )[3,4,5]; Furthermore, not all platforms will set the $wday and $yday elements. If these values are required, use "mktime" and "gmtime": use POSIX qw( mktime ); use POSIX::strptime qw( strptime ); my ($mday, $mon, $year) = ( POSIX::strptime( "2010/07/16", '%Y/%m/%d' ) )[3,4,5]; my $wday = ( gmtime mktime 0, 0, 0, $mday, $mon, $year )[6]; SEE ALSO
strptime(3) AUTHOR
Philippe M. Chiasson <gozer@cpan.org> Kim Scheibel <kim@scheibel.co.uk> REPOSITORY
http://svn.ectoplasm.org/projects/perl/POSIX-strptime/trunk/ COPYRIGHT
Copyright 2005 by Philippe M. Chiasson <gozer@cpan.org>. This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. See http://www.perl.com/perl/misc/Artistic.html perl v5.14.2 2010-07-16 POSIX::strptime(3pm)
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