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Top Forums Shell Programming and Scripting sed not working while passing the variable to print Post 302733305 by manas_ranjan on Tuesday 20th of November 2012 06:14:43 AM
Old 11-20-2012
sed not working while passing the variable to print

Hi

I have below sed to search and print particular line that matches in file and prints it, which is actually working fine as expected.

Code:
sed -n "/^2012-11-19 23:[0]*/p" filename

but if I replace date with the variable it seems it's not recognizing it and throwing out error

Code:
 v="2012-11-19"
sed -n 's/^'$v' 23:[0]*/p"  filename
 sed -n "s/^$v 23:[0]*/p"  filename

so can anyone help me resolving this??
 

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command(1)						      General Commands Manual							command(1)

NAME
command - execute a simple command SYNOPSIS
command_name [argument ...] DESCRIPTION
enables the shell to treat the arguments as a simple command, suppressing the shell function lookup. If command_name is not the name of the function, the effect of is the same as omitting command. Operands recognizes the following operands: command_name The name of a HP-UX command or a shell built-in command. argument One or more strings to be interpreted as arguments to command_name. The command is necessary to allow functions that have the same name as a command to call the command (instead of a recursive call to the function). Nothing in the description of is intended to imply that the command line is parsed any differently than any other simple command. For example, is not parsed in any special way that causes or to be treated other than a pipe operator or semicolon or that prevents function lookup on b or c. EXTERNAL INFLUENCES
Environment Variables determines the search path used during the command search. RETURN VALUE
exits with one of the following values: o If fails: 126 The utility specified by the command_name is found but not executable. 127 An error occurred in the utility or the utility specified by command_name is not found. o If does not fail: The exit status of is the same as that of the simple command specified by the arguments: command_name[argument ...] EXAMPLES
Create a version of the command that always prints the name of the new working directory whenever it is used: cd() { command "$@" >/dev/null pwd } Circumvent the redefined command above, and change directories without printing the name of the new working directory: SEE ALSO
getconf(1), sh-posix(1), confstr(3C). STANDARDS CONFORMANCE
command(1)
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