In HP-UX the date command does not have the "-d" switch like some other *nixes do. I'm working a simple script to tell me, given the day, month and year what day of the week that falls on.
Assuming valid day, month and year input (I'd perform quality checks on the input separately, but not shown here), would the following work for all dates? Or are there some corner cases that may not work correctly? I'm not worried about corner cases like way back in the 1500's when the Gregorian calendar 1st came online and how that might be screwed up.
The output is the output from a call to the 'cal' utility, plus the full name of the day of the week so that the named day of the week can be easily verified.
Code:
#!/bin/sh
day=$1
mth=$2
yr=$3
cal $mth $yr
set -A _WKDY Saturday Sunday Monday Tuesday Wednesday Thursday Friday
print ${_WKDY[$(cal $mth $yr | awk -vDD=$day 'FNR==3 {print ((7-$NF)+DD)%7}')]}
in awk,
Code:
FNR==3
means I skip the headers and am only concerned with the first week of the 'cal' output.
Breaking the math down:
Code:
(7-$NF)
Is an offset to "normalize" partial weeks since the first week of a month may have less than 7 days in it.
Code:
((7-$NF)+DD)
The offset is added to the numerical day of the month (DD)
Code:
((7-$NF)+DD)%7
The offset plus DD is then modded by 7 giving the numerical day of the week, of which, 0 is defined as Saturday, and 1-6 is defined as Sunday through Friday by how I set up the array.
I'm basically just wondering if anyone can break this given a modern date and valid inputs. (no using February 30th! :-) ) I can't break it, but I've a nagging suspicion I'm missing something.
Hi ,
I am working at Unix system,using c lang.
I need c fun which return the day of the week .
For example :
0- Sunday.
1- Monday.
....
10x. (4 Replies)
I need o get yesterday's day of week but im not exactly sure. the actual name is what i want. I can do it with numbers but im not sure with words. (3 Replies)
How to find the Day of the Week of the given Date using perl?
If I have a date in YYY--MM-DD format, how to find the DOW? Based on that, I need to find the following sunday.
Pls help. (5 Replies)
Hi All,
I have date in string format 'YYYY-MM-DD'. I want to know day of the week for this date.
Example. For '2005-08-21' my script should return '0' or Sunday
For '2005-08-22' it should return '1' or Monday
I want piece of code for HP-UX korn shell.
Appreciate reply on this. (5 Replies)
Hi all, I am trying to get dow from cal using below script
#! /bin/bash
YEAR=`echo $1 | cut -c 1-4`
MONTH=`echo $1 | cut -c 5-6`
DAY=`echo $1 | cut -c 7-8`
for i in 1 2 3 4 5 6 7
do
dayofweek=`cal $MONTH $YEAR | awk '$i == $DAY {printf("%s","$i")}'`
echo $dayofweek... (4 Replies)
I have been volunteered by my boss to be the sysadmin for our production redhat server. He asked me to tighten the security to avoid mishaps like "rm -f *" that occured not long ago.
Right now, we have 53 users sudo-ing into the machine and it is an audit nightmare. I am wondering if it... (15 Replies)
Hi everyone,
I have a shell script that merges many files down in to one, then removes unwanted lines, that part is working fine:
#!/bin/bash
FILES=/home/pi/temp/qbd/*
for f in $FILES
do
echo "Processing $f file..."
# take action on each file. $f store current file name
echo... (9 Replies)
Hi All,
I have the below requirement ,
if i give the week number for ex 41 i need to get the date for Monday and thursday for this given week. my expected output is 13/10/2014 (Monday's date) and 16/10/2014 (Thursday's date)
I am using GNU LINUX .
Pls help me with your thoughts.
Thanks in... (7 Replies)
Discussion started by: mohanalakshmi
7 Replies
LEARN ABOUT REDHAT
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week. (This is the default.)
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
BSD June 6, 1993 BSD
11-14-2012
