Hi
I want to read messages from multiple interfaces using one select() statement. Does anybody knows if I can specify multiple fds in the *readfds parameter? If yes, what's the max num of fds?
Something like the following:
fd_set descrSet = {0};
int retVal;
MyStructS *msg = NULL;
... (1 Reply)
Hello all,
I'm developing a deployment script at work and at one point it would need to display something like this:
Which version of ADMIN would you like to deploy?
1) 1.0.0 (store1, 10 Jan 2004)
2) 1.0.1 (store1, 20 Jun 2004)
3) 1.0.2 (store1, 15 Jul 2004)
Select a version :
I know... (5 Replies)
How do I create a script that provides a count of distinct values of a particular field in a file utilizing commonly available UNIX commands (sh or awk)?
Field1|Field2|Field3|Field4
AAA|BBB|CCC|DDD
111|222|333|777
AAA|EEE|ZZZ|EEE
111|555|333|444
AAA|EEE|CCC|DDD
111|222|555|444
For... (2 Replies)
Hi all,
Before I give up on using SELECT for my first attempt at creating a menu driven script, can anyone please advise if it is possible to include a line break for PS3, I've tried putting in a \n and it does not work.
Tried for both bash and ksh and both gives the same result. Preference... (3 Replies)
Hi All
I am using the below code to chose a file to view :
PS3="Select file to view : "
select FILE in `ls` QUIT
do
if ; then
clear
cat $FILE
else
break
fi
REPLY=''
done
Everything works fine as long as I am giving the correct choice .
But when i give a... (4 Replies)
I copied the below program to play around with displaying a list of items using the select command in ksh. When I put all items in the same line, it works fine. I am trying to use multiple lines instead of a single row...my list is too large for a single line. How do I get the line continuation... (3 Replies)
I have about 6000 files of the following format (three simplified examples shown; actual files have variable numbers of columns, but the same number of lines). I would like to concatenate the ID (*Loc*) and data lines, but not the others, as shown below. The result would be one large file (or... (3 Replies)
Hello,
I'm attempting to open multiple xterms and run a command as an SAP user via sudo using PSSH. So far, I'm able to run PSSH to a file of servers with no check for keys, open every xterm in to the servers in the file list, and SUDO to the SAP(ADM) user, but it won't do anything else... (11 Replies)
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)