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Top Forums Shell Programming and Scripting Add current date to the data file Post 302725643 by durden_tyler on Friday 2nd of November 2012 12:22:17 PM
Old 11-02-2012
Quote:
Originally Posted by LucyYani
...
I want this:
0.0230769,0.407692,0.307692,0,0.1,1.4,1,0,ADD DATE HERE,

im getting this:
11/02/12
0.00192308,0.0269231,0.0192308,0,0.1,1.4,1,0,

my script:
Code:
#!/bin/ksh
 
DIR=/export/home/yani_m/scripts/scrip_out_put/
DIR2=/export/home/yani_m/scripts/scrip_out_put/calc/
Date=$1
File22="disk_"$Date
Server=$2
iofiles=$DIR"/*"$Date"*_Ynr.dat"
gzipedfile=$File22".gz"
 
#SERVER2C       : ./test.ksh 20120716 NLEMM02
grep  c[0-9]t[0-9]d[0-9] $iofiles >> $DIR2/$File22
grep $Server $DIR2/$File22 |cut -d : -f 2 |cut -d , -f 1,2,9,10 | nawk -F "," 'BEGIN {Date=system("date +%D")}
{sumr=0;sumw=0;busy=0;wait=0}{sumr=sumr+$1}{sumw=sumw+$2}{wait=wait+$3}{busy=busy+$4}{maxr=$1 ; maxw=$2;maxb=$4 ;maxwe=$3}$1>=m
axr {maxr = $1} $2>=maxw {maxw = $2}$3>=maxwe {maxwe = $3}$4>=maxb {maxb = $4}
END{print sumr/NR "," sumw/NR ","  busy/NR "," wait/NR "," maxr "," maxw "," maxb "," maxwe ","}'>>/export/home/yani_m/scripts/FILE_TO_LOAD.dat
gzip $DIR2/$File22

...
The built-in "system" function of awk executes the command passed to it as a parameter. Hence the date is printed by your script.

You put the "system" function in the BEGIN section, hence the date was printed before the awk script started its processing.

The return value of the "system" function is the exit status of the command it executes. Since the "date" command was successful, "system" returned 0 and that was assigned to "Date" variable. Hence you see "0" in your output.

Here's another example:

Code:
$
$ # my dummy file that will be used by my simple awk script
$ cat -n f73
   1  AAA 10
   2  BBB 20
   3  CCC 30
$
$
$ # my shell script
$ cat -n f73_test.sh
   1  #!/usr/bin/bash
   2
   3  #
   4  # The "system" function runs the host (Unix/Linux) command
   5  # and prints the output, if any.
   6  # The awk script sums up the 2nd column in file "f73" and
   7  # prints it at the end.
   8  #
   9  awk ' BEGIN { dt = system("type bash") }
  10        { sum += $2 }
  11        END { print sum","dt }
  12      ' f73
  13
$
$ ./f73_test.sh
bash is /usr/bin/bash        <== this came from "BEGIN"
60,0                         <== and the "0" came from "END"
$
$

As pointed out by Subbeh, you may want to pass the date variable to your awk script. Thereby you'll be able to print it.

Like so -

Code:
$
$ # another shell script working on the same data file "f73"
$
$ cat -n f73_test1.sh
   1  #!/usr/bin/bash
   2
   3  # capture the 1st parameter in a variable called "mydate"
   4  mydate=$1
   5
   6  #
   7  # pass the variable "mydate" to the awk script that sums
   8  # the 2nd column in the file "f73"
   9  #
  10  awk -v dt=$mydate ' { sum += $2 }
  11                      END { print sum","dt }
  12                    ' f73
  13
$
$ # invoke the shell script now, passing a parameter
$ ./f73_test1.sh `date +%D`
60,11/02/12
$
$

tyler_durden
 

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