Hi,
Yeah you are right.
Now, I manage to do what I wanted. Following is the code snipet for that
Code:
for FileNameIndx in "${PATH535[@]}"
do
if [[ ! -e "dest_path/$FileNameIndx" ]]; then
ls -ltr "$FileNameIndx" | grep root | awk -F_ '{print $3,$0}' OFS=\t | sort -n | cut -f2- >> $File0"_0"
#ls -ltr "$FileNameIndx" | grep root | awk '{print string path $9}' string="$CONSTANT" path="$FileNameIndx" >> "$File0"
sort -nrk5 < $File0"_0" | awk -F_ '!x[$3]++' >> $File0"_1"
grep -in "vg" $File0"_1" | awk '{print path string $9}' string="/" path="$FileNameIndx" >> $FileName
echo "$FileNameIndx is copied"
else
echo "Check the FileName in ${PATHNAME[@]}"
fi
echo "---------------------------------------------------------"
echo ">>> DataFiles are from :" ${PATH535[@]}
echo "---------------------------------------------------------"
done
well, it is bit lengthy as I am beginner with script. But it works fine for me..
And about the "vgtree_1", I would prefer the
Code:
100 Oct 27 10:28 vgtee_1_ujf.root
with large file size.
thanks
emily,
---------- Post updated at 08:40 AM ---------- Previous update was at 06:04 AM ----------
Quote:
Originally Posted by RudiC
So you want to consider chars 1 - 7 of the filename only in order to find "duplicates" (No two or more digit integers possible?), and, if found, use the larger size file name?
I don't see any attempt to use either criterion in your code snippet? BTW, vgtee_1 would be a duplicate as well, wouldn't it?
Hi RudiC,
yes you are right, occurance of *1* is also duplication.
And now, the problem I am facing is following. The code snippet that I showed in my following mail is working fine but it leave a blank row on the top. I wonder if that can be removed somehow.
I would get the wrong results because of that.
so i have hundreds of files named history.20071112.tar
(history.YYYYMMDD.tar)
and im looking to extract one file out of each archive called status_YYYYMMDDHH:MM.lis
here is what i have so far:
for FILE in `cat dirlist`
do
tar xvf $FILE ./status_*
done
dirlist is a text... (4 Replies)
Hi,
I have 20 files which have respective 50 lines with different values.
I would like to process each line of the 50 lines in these 20 files one at a time and do an average of 3rd field ($3) of these 20 files. This will be output to an output file.
Instead of using join to generate whole... (8 Replies)
hi everyone!
I already posted it in scripts, I'm sorry, it's doubled
I'd like to extract a single column from 5 different files and put them together in an output file. I saw a similar question for 2 input files, and the line of code workd very well, the code is:
awk 'NR==FNR{a=$2; next}... (1 Reply)
hi everyone!
I'd like to extract a single column from 5 different files and put them together in an output file. I saw a similar question for 2 input files, and the line of code workd very well, the code is:
awk 'NR==FNR{a=$2; next} {print a, $2}' file1 file2
I added the file3, file4 and... (10 Replies)
Hi,
I have several files that look like this:
File1.txt
Data1
Data2
Data20
File2.txt
Data1
Data5
Data10
File3.txt
Data1
Data2
Data17
File4.txt (6 Replies)
Hi Everyone,
I'm really new to all this so I'm really hoping someone can help. I have a directory with ~1000 lists from which I want to extract lines from and write to new files. For simplicity lets say they are shopping lists and I want to write out the lines corresponding to apples to a new... (2 Replies)
Hello there,
I am trying to extract (string) information ( a list words) from 4 files and then put the results into 1 file. Currently I am doing this using grep -f list.txt file1 . and repeat the process for the other 3 files. The reasons i am doing that (a) I do know how to code (b) each file... (4 Replies)
consider the following is the contents of the file
cat 11.sql
drop procedure if exists hoop1 ;
Delimiter $$
CREATE PROCEDURE hoop1(id int)
BEGIN
END
$$
Delimiter ;
.
.
.
.
drop procedure if exists hoop2;
Delimiter $$
CREATE PROCEDURE hoop2(id int)
BEGIN
END
$$ (8 Replies)
Hey,
I have number of .tgz files and want to extract the file with the ending *results.txt from each one.
I have tried
for file in *.tgz; do tar --wildcards -zxf $file *results.txt; doneas well as
list=$(ls *.tgz)
for i in $list; do tar --wildcards -zxvf $i *.results.txt; done... (1 Reply)
Discussion started by: jfern
1 Replies
LEARN ABOUT PHP
geoip_region_name_by_code
GEOIP_REGION_NAME_BY_CODE(3) 1 GEOIP_REGION_NAME_BY_CODE(3)geoip_region_name_by_code - Returns the region name for some country and region code comboSYNOPSIS
string geoip_region_name_by_code (string $country_code, string $region_code)
DESCRIPTION
The geoip_region_name_by_code(3) function will return the region name corresponding to a country and region code combo.
In the United States, the region code corresponds to the two-letter abbreviation of each state. In Canada, the region code corresponds to
the two-letter province or territory code as attributed by Canada Post.
For the rest of the world, GeoIP uses FIPS 10-4 codes to represent regions. You can check http://www.maxmind.com/app/fips10_4 for a
detailed list of FIPS 10-4 codes.
This function is always available if using GeoIP Library version 1.4.1 or newer. The data is taken directly from the GeoIP Library and not
from any database.
PARAMETERS
o $country_code
- The two-letter country code (see geoip_country_code_by_name(3))
o $region_code
- The two-letter (or digit) region code (see geoip_region_by_name(3))
RETURN VALUES
Returns the region name on success, or FALSE if the country and region code combo cannot be found.
EXAMPLES
Example #1
A geoip_region_name_by_code(3) example using region code for US/Canada
This will print the region name for country CA (Canada), region QC (Quebec).
<?php
$region = geoip_region_name_by_code('CA', 'QC');
if ($region) {
echo 'Region name for CA/QC is: ' . $region;
}
?>
The above example will output:
Region name for CA/QC is: Quebec
Example #2
A geoip_region_name_by_code(3) example using FIPS codes
This will print the region name for country JP (Japan), region 01.
<?php
$region = geoip_region_name_by_code('JP', '01');
if ($region) {
echo 'Region name for JP/01 is: ' . $region;
}
?>
The above example will output:
Region name for JP/01 is: Aichi
PHP Documentation Group GEOIP_REGION_NAME_BY_CODE(3)
10-28-2012
