Hi,
I have a date input in MMDDYYYY format..
I have to give the day (whether that DD is sunday/monday...)
Is there any command for it...
Or do I have to write a script for that...
Thanks in Advance
Yeheya (1 Reply)
Hi, I have been trying just about every unix command to come up with yesterday's date (today's date - 1). I have seen all of the help on this forum, and none of it seems to work for me here. We are using Sun Solaris 9 Unix. I am using this script to create a .txt file with ftp commands that I will... (2 Replies)
It's easy as pie to get the date minus one day on opensolaris:
date -d "-1 day" +"%Y%m%d"run this command on our crappy Solaris 10 machines however (which I'm guessing doesn't have GNU date running on it) and you get:
date: illegal option -- d
date: illegal option -- 1
date: illegal option --... (5 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
Hi,
Can any one help to find out the day for the given date in AIX. If we giving date as "YYYYMMDD" it should display its day.
eg:if the input is "20120103", expected output is "tuesday" :wall:
Pls help (7 Replies)
Hello All,
I am writing a script in Sun Solaris
I want the date for "day before yesterday", i got the yesterday's date by this command TZ=GMT+24 date +%b" "%d.
Please suggest me some code to get the date for day before yesterday (6 Replies)
I need to get the next day's date of the user entered date
for example:
Enter date (yyyy/mm/yy):
2013/10/08I need to get the next day's date of the user entered date
Desired Output:
2013/10/09Though there are ways to achieve this is Linux or Unix environment (date command) ,I need to... (1 Reply)
Hi Team,
We have a requirement as follows.
If a date 20141220 as parameter to the script, then the script has to return the output as 20141219.
i.e given date - 1.
The requirement is simple. But it should satisfy leap year, the months having 31 and 30 days, the date in which day light... (9 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT MINIX
date
DATE(1) General Commands Manual DATE(1)NAME
date - print or set the date and time
SYNOPSIS
date [-qsu] [[MMDDYY]hhmm[ss]] [+format]
OPTIONS -q Read the date from stdin
-s Set the time (implicit for -q or a date string)
-u Print the date as GMT
-t Use this number of seconds instead of current time
EXAMPLES
date # Print the date and time
date 0221921610 # Set date to Feb 21, 1992 at 4:10 p.m.
DESCRIPTION
With the -q flag or a numeric argument, date sets the GMT time and date. MMDDYY refers to the month, day, and year; hhmmss refers to the
hour, minute and second. Each of the six fields must be exactly two digits, no more and no less. date always display the date and time,
with the default format for the system. The -u flag request GMT time instead of local time. A format may be specified with a + followed
by a printf-like string with the following options:
%% % character
%A Name of the day
%B Name of the month
%D mm/dd/yy
%H Decimal hour on 2 digits
%I Decimal hour modulo 12 on 2 digits
%M Decimal minute on 2 digits
%S Decimal seconds on 2 digits
%T HH:MM:SS
%U Decimal week number, Sunday being first day of week
%W Decimal week number, Monday being first day of week
%X Same as %T
%Y Decimal year on 4 digits
%Z Time Zone (if any)
%a Abbreviated name of the day
%b Abbreviated name of the month
%c Appropriate date & time (default format)
%d Decimal day of the month on 2 digits
%e Same as %d, but a space replaces leading 0
%h Same as %b
%j Decimal dey of the year on 3 digits
%m Decimal month on 2 digits
%n Newline character
%p AM or PM
%r 12-hour clock time with AM/PM
%s Number of seconds since the epoch
%t Tab character
%w Decimal day of the week (0=Sunday)
%x Same as %D
%y Decimal year on 2 digits
SEE ALSO time(2), ctime(3), readclock(8).
DATE(1)