Sponsored Content
Full Discussion: Awk OFS issues
Top Forums Shell Programming and Scripting Awk OFS issues Post 302719149 by elixir_sinari on Monday 22nd of October 2012 07:20:42 AM
Old 10-22-2012
Quote:
Originally Posted by 02JayJay02
Hi, thankyou for the help but Im still getting the below error message after trying your suggestion

Code:
awk: can't open BEGIN {OFS="\t";} {print $1,$2,$3,$4,$5,$6,$7,$8,$9;}

Please post (exactly) what you typed in.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

OFS in awk

Hi, I have these out put field seperator changed to "|" in my awk command, but it didn't give me the result. Can someone help me find out why? ======================================= /bin/awk 'BEGIN { OFS="|" } { print $0 }' list.tmp.$$ > listtmp.$$ =======================================... (1 Reply)
Discussion started by: whatsfordinner
1 Replies

2. Shell Programming and Scripting

OFS in awk.

OFS is inbuild command in awk. I have a file file.txt abc : def : ghi jkl : mno: pqr stu : vwx :yzz code i used: awk -F ":" 'BEGIN {OFS="|"} {print $1,$2}' file.txt output: abc def jkl mno stu vwx but as i have used OFS="|" and i am expecting output as: abc | def jkl... (4 Replies)
Discussion started by: salil2012
4 Replies

3. Shell Programming and Scripting

AWK - OFS

Hi All, I have a comma seperated delimited file with 10 columns. I need to convert it into TAB seperated delimited file. awk -F"," '{print $1"\t"$2"\t"$3"\t"$4"\t"$5"\t"$6"\t"$7"\t"$8"\t"$9"\t"$10}' a.txt >> b.txt how to use OFS to get the same output. I have tried by googling, but it... (5 Replies)
Discussion started by: Amit.Sagpariya
5 Replies

4. Shell Programming and Scripting

Parsing XML in awk : OFS does not work as expected

Hi, I am trying to parse regular XML file where I have to reduce number of decimal points in some xml elements. I am using following AWK command to achive that : #!/bin/ksh EDITCMD='BEGIN { FS = ""; OFS=FS } { if ( $3 ~ "*\\.*" && length(substr($3,1+index($3,"."))) == 15 ) {... (4 Replies)
Discussion started by: martin.franek
4 Replies

5. UNIX for Dummies Questions & Answers

Problem with AWK and OFS

I have a file that looks like this: Infile.seq I want to output the DNA sequence and add the filename as the identifier. The output file should look like this: I am using the following code but I do not understand why the sequence is not in the output: awk 'BEGIN { RS =... (11 Replies)
Discussion started by: Xterra
11 Replies

6. Shell Programming and Scripting

Awk OFS issues

Hi Im trying to tidy up the output of a who command when it writes to a log, everything I've tried doesnt seem to work though, any help would be massively appreciated. Im using the awk command to set the OFS as tab. #!/bin/bash who >> /export/home/tjmoore/logusers awk -F 'BEGIN... (3 Replies)
Discussion started by: 02JayJay02
3 Replies

7. UNIX for Dummies Questions & Answers

OFS in awk

Hello, I have an issue with adding commas as delimiters in this scenario: cat xtr3.rpl|head -5|awk 'BEGIN {OFS=","} {print $1,$2,$3,$4}' Produces this output: 00530083,0000000471,000000000000.00,000000000000.00 00530085,0000000471,000000000000.00,000000000000.00... (10 Replies)
Discussion started by: MIA651
10 Replies

8. Shell Programming and Scripting

OFS print awk

file: sasa|asasa|asasa|asas erer|Erer|rere|ererer Output needed : sasa:asasa:asasa:asas erer:Erer:rere:ererer Im getting output, when i use the $1,$2. awk -F'|' 'BEGIN{OFS=":";} {print $1,$2; }' file Output : sasa:asasa erer:Erer But when i need the whole column, i... (5 Replies)
Discussion started by: Ramesh M
5 Replies

9. Shell Programming and Scripting

OFS does not apply to few records in awk

Hi , I am having a problem with my awk oneliner , which for some reason leaves the first two records Input File $ cat file1 A1:B1:C1:NoLimit M1:M2:M3:Limit A2:B2:C2,C3,C4,C5 A3:B3:C3,C4,C5,C6,C7Desired output A1,B1,C1,NoLimit M1,M2,M3,Limit A2,B2,C2 ,,,C3 ,,,C4 ,,,C5 A3,B3,C3... (5 Replies)
Discussion started by: chidori
5 Replies

10. Shell Programming and Scripting

awk - OFS printing duplicate. Why?

Why the following code printing duplicate records? bash-4.1$ cat rm1 c1 c2 c3 l1 2 3 4 l2 2 3 2 bash-4.1$ awk '{print $0} OFS = "\n"' rm1 c1 c2 c3 c1 c2 c3 l1 2 3 4 l1 2 3... (4 Replies)
Discussion started by: quincyjones
4 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 01:36 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy