Replace date on a line with current date Post: 302715825

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Date One Week Ago From Given Date, Not From Current Date

Hi all, I've used various scripts in the past to work out the date last week from the current date, however I now have a need to work out the date 1 week from a given date. So for example, if I have a date of the 23rd July 2010, I would like a script that can work out that one week back was...

2. UNIX for Dummies Questions & Answers

Delete a row from a file if one column containing a date is greater than the current system date

Hello gurus, I am hoping someone can help me with the required code/script to make this work. I have the following file with records starting at line 4: NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~...

3. Shell Programming and Scripting

Fetch date of 7 years back from current date in Perl

$beginDate = substr(DateCalc("today", "-7Days"),0,8); This fetches the date 7 days back Can I fetch the date before 7 years from todays date in Perl using same syntax Use code tags, see PM.

4. Shell Programming and Scripting

[Solved] Replace yesterday date with today's date except from the first line

Hello, I have a file like this: 2012112920121130 12345620121130msABowwiqiq 34477420121129amABamauee e7748420121130ehABeheheei in case the content of the file has the date of yesterday within the lines containing pattern AB this should be replaced by the current date. But if I use...

5. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error...

6. UNIX for Beginners Questions & Answers

UNIX script to replace old date with current date dynamically in multiple files present in a folder

I am trying to work on a script where it is a *(star) delimited file has a multiple lines starts with RTG and 3rd column=TD8 I want to substring the date part and I want to replace with currentdate minus 15 days. Here is an example. iam using AIX server $ cat temp.txt RTG*888*TD8*20180201~...

7. Linux

How to calculate the quarter end date according to the current date in shell script?

Hi, My question is how to calculate the quarter end date according to the current date in shell script?

8. UNIX for Beginners Questions & Answers

“sed” replace date in text file with current date

We want to call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below: abc.txt ------------------ Code: line1 line2 line3 $$EDWS_DATE_INSERT=08-27-2019 line4 $$EDWS_PREV_DATE_INSERT=08-26-2019 I am trying to write a...

9. UNIX for Beginners Questions & Answers

How to replace a parameter(variable) date value inside a text files daily with current date?

Hello All, we what we call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below: abc.txt ------------------ line1 line2 line3 $$EDWS_DATE_INSERT=08-27-2019 line4 $$EDWS_PREV_DATE_INSERT=08-26-2019 I am trying to...

10. UNIX for Beginners Questions & Answers

Replace date in file every day with current date

I Have text like XXX_20190908.csv.gz need to replace Only date in this format with current date every day Thanks!

LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)