Hello All,
I have a string "CP_STATUS OSSRC_R6_0_Shipment_R1H_CU AOM_901046 R1H_LLSV1_2008031", and I just want to extract LLSV1, but I dont get the expected result when using the sed command below.
# echo "CP_STATUS OSSRC_R6_0_Shipment_R1H_CU AOM_901046 R1H_LLSV1_2008031" | awk '{print... (4 Replies)
I am trying to do some thing like this ..
In a file , if pattern found insert new pattern at the begining of the line containing the pattern.
example:
in a file I have this.
gtrow0unit1/gctunit_crrownorth_stage5_outnet_feedthru_pin
if i find feedthru_pin want to insert !! at the... (7 Replies)
Hi
i want to search two pattern on same line and replace onther pattern..
INPut file
aaaa bbbbb nnnnnn ttttt
cccc bbbbb nnnnnn ppppp
dddd ccccc nnnnnn ttttt
ffff bbbbb oooooo ttttt
now i want replace this matrix like.. i want search for "bbbbb","nnnnnn" and search and replace for... (4 Replies)
Hello,
I need to find all *.xml files that matched by pattern on Linux. I need to have written the file name on the screen and then change the pattern in the file just was found.
For instance.
I can start the script with arguments for keyword and for value, i.e
script.sh keyword... (1 Reply)
I need this.
aaa
OOOOO
bbb
ccc
OOOOO
ddd
fff
ggg
OOOOO
iii
OOOOO
I need all OOOOO replaced with PPPPP, but only change after the pattern ggg. So the first two OOOOO should not be changed.
OUTPUT should be :-
aaa (2 Replies)
I have a pattern
username:x:32005:32006::/usr/local/user:/bin/bash
I need to match the line containing username and replace /bin/bash with /usr/local/my/bin/noshell
So it becomes
username:x:32005:32006::/usr/local/user:/usr/local/my/bin/noshell (7 Replies)
Hi experts , im new to Unix,AWK ,and im just not able to get this right.
I need to match for some patterns if it matches I need to print the next few words to it.. I have only three such conditions to match… But I need to print only those words that comes after satisfying the first condition..... (2 Replies)
Im using the command below , but thats not the output that i want. it only prints the odd and even numbers.
awk '{if(NR%2){print $0 > "1"}else{print $0 > "2"}}'
Im hoping for something like this
file1:
Text hi this is just a test
text1 text2 text3 text4 text5 text6
Text hi... (2 Replies)
The intended result should be :
PDF converters
'empty line'
gpdftext and pdftotext?xml version="1.0"?>
xml:space="preserve"><note-content version="0.1" xmlns:/tomboy/link" xmlns:size="http://beatniksoftware.com/tomboy/size">PDF converters
gpdftext and pdftotext</note-content>... (9 Replies)
Discussion started by: Klasform
9 Replies
LEARN ABOUT DEBIAN
pam_ftp
PAM_FTP(8) Linux-PAM Manual PAM_FTP(8)NAME
pam_ftp - PAM module for anonymous access module
SYNOPSIS
pam_ftp.so [debug] [ignore] [users=XXX,YYY,...]
DESCRIPTION
pam_ftp is a PAM module which provides a pluggable anonymous ftp mode of access.
This module intercepts the user's name and password. If the name is ftp or anonymous, the user's password is broken up at the @ delimiter
into a PAM_RUSER and a PAM_RHOST part; these pam-items being set accordingly. The username (PAM_USER) is set to ftp. In this case the
module succeeds. Alternatively, the module sets the PAM_AUTHTOK item with the entered password and fails.
This module is not safe and easily spoofable.
OPTIONS
debug
Print debug information.
ignore
Pay no attention to the email address of the user (if supplied).
ftp=XXX,YYY,...
Instead of ftp or anonymous, provide anonymous login to the comma separated list of users: XXX,YYY,.... Should the applicant enter one
of these usernames the returned username is set to the first in the list: XXX.
MODULE TYPES PROVIDED
Only the auth module type is provided.
RETURN VALUES
PAM_SUCCESS
The authentication was successful.
PAM_USER_UNKNOWN
User not known.
EXAMPLES
Add the following line to /etc/pam.d/ftpd to handle ftp style anonymous login:
#
# ftpd; add ftp-specifics. These lines enable anonymous ftp over
# standard UN*X access (the listfile entry blocks access to
# users listed in /etc/ftpusers)
#
auth sufficient pam_ftp.so
auth required pam_unix.so use_first_pass
auth required pam_listfile.so
onerr=succeed item=user sense=deny file=/etc/ftpusers
SEE ALSO pam.conf(5), pam.d(5), pam(7)AUTHOR
pam_ftp was written by Andrew G. Morgan <morgan@kernel.org>.
Linux-PAM Manual 06/04/2011 PAM_FTP(8)
10-09-2012
