Solaris had a sort bug once I recall, but it was more subtle. Try using the -k method of specifying fields and sort direction and such. The +1 -2 notation is obsolescent - LINUX does not have it any more, and 0-based! The -k notation is 1-based, not zero-based, which might be more normal human friendly. BTW, +1 says sort on column 2 and following. I suppose column 1 is the file name?
Some sort of persistent JAVA container could do the testing and storing without a sort, perhaps in a tree. You can put the data into a structure mapped to a flat file, for instance. One possible advantage is that you can prune the set on the fly, if you are not interested in the full set. Also, you can do controlled thread parallelism. It is a lot faster than sort or an SQL RDBMS ETL approach.
Sort can also be sped up with parallelism in bash, on nicer systems with /dev/fd/[0-9]* and ksh (or using named pipes), using sort merge and pipes:
Hi All,
I have a file 1.txt which has the duplicate dns entries as shown:
Name: 000f9fbc6738.net.in|Addresses: 10.241.66.169, 10.84.2.222,212.241.66.170
Name: 001371e8ed3e.net.in|Addresses: 10.241.65.153, 10.84.1.101
Name: 00e06f5bd42a.net.in|Addresses: 10.72.19.218,... (6 Replies)
My data is something like shown below.
date1 date2 aaa bbbb ccccc
date3 date4 dddd eeeeeee ffffffffff ggggg hh
I want the output like this
date1date2 aaa eeeeee
I serached in the forum but didn't find the exact matching solution. Please help. (7 Replies)
Hi to all.
I'm trying to sort this with the Unix command sort.
user1:12345678:3.5:2.5:8:1:2:3
user2:12345679:4.5:3.5:8:1:3:2
user3:12345687:5.5:2.5:6:1:3:2
user4:12345670:5.5:2.5:5:3:2:1
user5:12345671:2.5:5.5:7:2:3:1
I need to get this:
user3:12345687:5.5:2.5:6:1:3:2... (7 Replies)
Hi Everybody,
I am just new to UNIX as well as to this forum. I have a text file with 10,000 coloumns and each coloumn contains values separated by space. I want to separate them into new coloumns..the file is something like this
as ad af 1 A
as ad af 1 D
...
...
1 and A are in one... (7 Replies)
Hello all -
I am to this forum and fairly new in learning unix and finding some difficulty in preparing a small shell script. I am trying to make script to sort all the files given by user as input (either the exact full name of the file or say the files matching the criteria like all files... (3 Replies)
Hi All, Need Suggestion, Want to sort a file using awk & sed to get required, output as below, such that each LUN shows correct WWPN and FA port Numbers correctly:
Required output:
01FB 10000000c97843a2 8C 0
01FB 10000000c96fb279 9C 0
22AF 10000000c97843a2 8C 0
22AF 10000000c975adbd ... (10 Replies)
Input file:
100%ABC2 3.44E-12 USA
A2M%H02579 0E0 UK
100%ABC2 5.34E-8 UK
100%ABC2 3.25E-12 USA
A2M%H02579 5E-45 UK
Output file:
100%ABC2 3.44E-12 USA
100%ABC2 3.25E-12 USA
100%ABC2 5.34E-8 UK
A2M%H02579 0E0 UK
A2M%H02579 5E-45 UK
Code try:
sort -k1,1 -g -k2 -r input.txt... (2 Replies)
Hi Experts,
I have a filelist collected from another server , now want to sort the output using date/time stamp filed.
- Filed 6, 7,8 are showing the date/time/stamp.
Here is the input:
#----------------------------------------------------------------------
-rw------- 1 root ... (3 Replies)
Any good way to check if code has the required output
# /sbin/sysctl net.ipv4.icmp_echo_ignore_broadcasts
net.ipv4.icmp_echo_ignore_broadcasts = 1
/sbin/sysctl net.ipv4.icmp_echo_ignore_broadcasts | grep "= 1"
net.ipv4.icmp_echo_ignore_broadcasts = 1
What I can think of is above, and it... (16 Replies)
I have the below contents in a file after making the below curl call
curl ... | grep -E "state|Rno" | paste -sd',\n' | grep "Disconnected" > test
"state" : "Disconnected",, "Rno" : "5554f1d2"
"state" : "Disconnected",, "Rno" : "10587563"
"state" : "Disconnected",, "Rno" :... (2 Replies)
Discussion started by: Vaibhav H
2 Replies
LEARN ABOUT DEBIAN
sort
sort(3perl) Perl Programmers Reference Guide sort(3perl)NAME
sort - perl pragma to control sort() behaviour
SYNOPSIS
use sort 'stable'; # guarantee stability
use sort '_quicksort'; # use a quicksort algorithm
use sort '_mergesort'; # use a mergesort algorithm
use sort 'defaults'; # revert to default behavior
no sort 'stable'; # stability not important
use sort '_qsort'; # alias for quicksort
my $current;
BEGIN {
$current = sort::current(); # identify prevailing algorithm
}
DESCRIPTION
With the "sort" pragma you can control the behaviour of the builtin "sort()" function.
In Perl versions 5.6 and earlier the quicksort algorithm was used to implement "sort()", but in Perl 5.8 a mergesort algorithm was also
made available, mainly to guarantee worst case O(N log N) behaviour: the worst case of quicksort is O(N**2). In Perl 5.8 and later,
quicksort defends against quadratic behaviour by shuffling large arrays before sorting.
A stable sort means that for records that compare equal, the original input ordering is preserved. Mergesort is stable, quicksort is not.
Stability will matter only if elements that compare equal can be distinguished in some other way. That means that simple numerical and
lexical sorts do not profit from stability, since equal elements are indistinguishable. However, with a comparison such as
{ substr($a, 0, 3) cmp substr($b, 0, 3) }
stability might matter because elements that compare equal on the first 3 characters may be distinguished based on subsequent characters.
In Perl 5.8 and later, quicksort can be stabilized, but doing so will add overhead, so it should only be done if it matters.
The best algorithm depends on many things. On average, mergesort does fewer comparisons than quicksort, so it may be better when
complicated comparison routines are used. Mergesort also takes advantage of pre-existing order, so it would be favored for using "sort()"
to merge several sorted arrays. On the other hand, quicksort is often faster for small arrays, and on arrays of a few distinct values,
repeated many times. You can force the choice of algorithm with this pragma, but this feels heavy-handed, so the subpragmas beginning with
a "_" may not persist beyond Perl 5.8. The default algorithm is mergesort, which will be stable even if you do not explicitly demand it.
But the stability of the default sort is a side-effect that could change in later versions. If stability is important, be sure to say so
with a
use sort 'stable';
The "no sort" pragma doesn't forbid what follows, it just leaves the choice open. Thus, after
no sort qw(_mergesort stable);
a mergesort, which happens to be stable, will be employed anyway. Note that
no sort "_quicksort";
no sort "_mergesort";
have exactly the same effect, leaving the choice of sort algorithm open.
CAVEATS
As of Perl 5.10, this pragma is lexically scoped and takes effect at compile time. In earlier versions its effect was global and took
effect at run-time; the documentation suggested using "eval()" to change the behaviour:
{ eval 'use sort qw(defaults _quicksort)'; # force quicksort
eval 'no sort "stable"'; # stability not wanted
print sort::current . "
";
@a = sort @b;
eval 'use sort "defaults"'; # clean up, for others
}
{ eval 'use sort qw(defaults stable)'; # force stability
print sort::current . "
";
@c = sort @d;
eval 'use sort "defaults"'; # clean up, for others
}
Such code no longer has the desired effect, for two reasons. Firstly, the use of "eval()" means that the sorting algorithm is not changed
until runtime, by which time it's too late to have any effect. Secondly, "sort::current" is also called at run-time, when in fact the
compile-time value of "sort::current" is the one that matters.
So now this code would be written:
{ use sort qw(defaults _quicksort); # force quicksort
no sort "stable"; # stability not wanted
my $current;
BEGIN { $current = print sort::current; }
print "$current
";
@a = sort @b;
# Pragmas go out of scope at the end of the block
}
{ use sort qw(defaults stable); # force stability
my $current;
BEGIN { $current = print sort::current; }
print "$current
";
@c = sort @d;
}
perl v5.14.2 2010-12-30 sort(3perl)