How to find out whether a file exists with the help of regular expression?
Hi all
I have a list of file names in array. But this file names are not exact. so i want to search whether a file exists or not using regular expression.
code snippet:
over here "*EQST*" should be treated as a regular expression. and the Actual file name in the directory will be something like 'Exp_BK_FT_T_EQST.txt'.
So how should i do this?
The above could is taking *EQST* as a string and trying to search with the same name.
TIA
Regards
Ganesh
---------- Post updated at 02:51 PM ---------- Previous update was at 02:45 PM ----------
Hey got it no need to reply. i just had to remove the double quotes from the if clause.
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Discussion started by: digioleg54
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LEARN ABOUT CENTOS
ausearch_add_regex
AUSEARCH_ADD_REGEX(3) Linux Audit API AUSEARCH_ADD_REGEX(3)NAME
ausearch_add_regex - use regular expression search rule
SYNOPSIS
#include <auparse.h>
int ausearch_add_regex(auparse_state_t *au, const char *expr);
DESCRIPTION
ausearch_add_regex adds one search condition based on a regular expression to the current audit search expression. The search conditions
can then be used to scan logs, files, or buffers for something of interest. The regular expression follows the posix extended regular
expression conventions, and is matched against the full record (without interpreting field values).
If an existing search expression E is already defined, this function replaces it by (E && this_regexp).
RETURN VALUE
Returns -1 if an error occurs; otherwise, 0 for success.
SEE ALSO ausearch_add_expression(3), ausearch_add_item(3), ausearch_clear(3), ausearch_next_event(3), regcomp(3).
AUTHOR
Steve Grubb
Red Hat Sept 2007 AUSEARCH_ADD_REGEX(3)