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Top Forums Shell Programming and Scripting shell script help needed to manage FTP automation Post 302702663 by Corona688 on Tuesday 18th of September 2012 04:31:10 PM
Old 09-18-2012
Does your system have ssh or scp available? ftp is extremely hard to automate.

Quote:
Originally Posted by ImranBD
1. I am unable to use delete command to delete data in the ftp location (I have permission to delete).
I don't see your script deleting anything. What are you trying to delete, how do you try to delete it, and in what way does it not work?
Quote:
2. I don't want to download or delete data which are under precessing, file will have .curr extention.
Please explain your script further. I'm not entirely clear on what your first step does. Please show what ends up in your $TEMP_LIST_FILE.

Your second step is a pointless and dangerous use of backticks.

I also suspect you don't need to run ftp 5,000 times to download 5,000 files.

Why are you putting the second ftp in backticks if you never use the result?

I don't think you need mget to download individual files.

Your here-documents will not work, because the ending EOF must be at the beginning of the line, not indented.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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