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Top Forums Shell Programming and Scripting carriage returns within quotation marks causing new lines in csv Post 302695587 by Don Cragun on Monday 3rd of September 2012 07:43:14 AM
Old 09-03-2012
Quote:
Originally Posted by pamu
Just add quotes to Don's solution....

Code:
awk '/^["]/{if(out != "") print out;out = $0;next}
        {out = out" "$0}
END     {if(out != "") print out}' input

Adding quotes would produce:
Code:
"apple","banana","orange"
"pineapple","grape","straw berry"
"apple","banana","cherry"

instead of:
Code:
"apple","banana","orange"
"pineapple","grape","strawberry"
"apple","banana","cherry"

for the sample input that was given in the first post in this thread. You have to choose whether you want"strawberry"and"123 Maple St.Apt. C."OR"straw berry"and"123 Maple St. Apt. C.". If you want"strawberry"and"123 Maple St. Apt. C.", you need to specify the logic that should be used to determine when a space is needed and when it isn't.

Note also that in koeji's original post explicitly stated:"I have a csv file with 3 columns.", but the"actual sample"provided in a later post has:
Code:
"Doe", "John", "N", "123 Maple St.
Apt. C."

which not only has 4 fields (instead of 3), but also has <comma><space> separated fields instead of <comma> separated fields.

With the original problem statement, I had considered pairing three sets of <double-quote> characters instead of just looking for lines that didn't start with a <double-quote>. In the future, please post real examples, instead of simplified examples that don't match the actual input you expect to be processing.
 

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