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Top Forums UNIX for Dummies Questions & Answers Combine columns from 100 files with same structure Post 302695255 by genehunter on Sunday 2nd of September 2012 10:59:40 AM
Old 09-02-2012
Question Combine columns from 100 files with same structure

Hi,
I have a bunch of files with the following format.
Code:
PUR.1.9 
30910 0.024 0.926 0.050
36587 0.024 0.927 0.049
91857 0.023 0.928 0.049
105797 0.024 0.927 0.049
146659 0.024 0.927 0.049
152695 0.024 0.927 0.049
192118 0.022 0.930 0.048
193310 0.018 0.936 0.046

PUR.2.9  
30910 0.028 0.652 0.320
36587 0.027 0.652 0.320
105797 0.027 0.652 0.321
146659 0.027 0.652 0.321
152695 0.027 0.652 0.321
181843 0.027 0.653 0.321
192118 0.026 0.653 0.321
193310 0.023 0.655 0.322

PUR.3.9  
30910 0.001 0.088 0.911
36587 0.001 0.087 0.912
91857 0.001 0.086 0.913
105797 0.001 0.086 0.913
152695 0.001 0.087 0.913
181843 0.001 0.086 0.914
192118 0.001 0.082 0.917
193310 0 0.076 0.923

I would like to have col2-4 from all files output side by side with just col1 being the unique identifier across all files.
result.txt
Code:
30910	0.024	0.926	0.05	0.028	0.652	0.32	0.001	0.088	0.911
36587	0.024	0.927	0.049	0.027	0.652	0.32	0.001	0.087	0.912
91857	0.023	0.928	0.049	-	-	-	0.001	0.086	0.913
105797	0.024	0.927	0.049	0.027	0.652	0.321	0.001	0.086	0.913
146659	0.024	0.927	0.049	0.027	0.652	0.321	-	-	-
152695	0.024	0.927	0.049	0.027	0.652	0.321	0.001	0.087	0.913
181843	-	-	-	0.027	0.653	0.321	0.001	0.086	0.914
192118	0.022	0.93	0.048	0.026	0.653	0.321	0.001	0.082	0.917
193310	0.018	0.936	0.046	0.023	0.655	0.322	0	0.076	0.923

Please help
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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