and the code to extract last nth day's date is
START=`TZ="GMT+$((24*N))" date +"%Y %b %d"`
---------- Post updated at 02:50 AM ---------- Previous update was at 02:44 AM ----------
Yes Pamu, i can do this too, good option but in case if date format changed.
will this work?
Specially in awk -F ":" the ":" symbol. beacuse in another file this can be "-" or ";"
-F ":" this used as field separator. If date format changed by that means field separator changed then we have to implement that to the code. But this is not major change you can do it easily.
for START variable..
You can use below code to assign date variable to one day ahead of today's date...
How I can get the logs that are getting stored in specific location in unix server
through an Apache web server installed in unix server?
Requirement is to access the logs through the URL in windows browser without any access. (1 Reply)
I want to write a shell script that deletes all log files in a directory that are older than 30 days except for 3 files:
I am using the following command:
find /tmp/logs -name "*.log" -mtime +30 -exec rm -f {} \;But this command deletes all the log files.
How can i modify this script that... (5 Replies)
i am using HP-UX OS......
delete logs older than 60 days
find -mtime +60 | grep -i '.*log' | xargs rm
-mtime is nt available in HP-UX, pls tell me other option ? (2 Replies)
I have crontab job a tar file to a directory ( tar -cvf /tmp/backup/or.`date +%m%d%y`. /ora/db/* ) , it will do it every day . Now I don't want to keep too much files , I just want to keep the file for 90 days , can advise if I want to remove the backup file which are elder than 90 days , can... (1 Reply)
Hi Team,
Have to write a shell script to pick only 1 hr logs from the generated logfile and send it to other logfile.
Thanks & Regards,
Indu (3 Replies)
As i am working in unix environment so i have an logs that is created by my application at the following location that is
/opt/app/glac/current/servers/ops/logs
inside the logs directory there are different kinds of logs(that is the file having extension as .log ) have been created... (1 Reply)
Dear Experts,
I need some help to get the time stamps from the Unix logs. Basically I am want to analyze which step is taking more time. Please give me some inputs. Thanks a lot for your help.
I have got different codes for each for phase as we can see in the logs
00002 – UPDT Starting... (5 Replies)
Discussion started by: srikanth38
5 Replies
LEARN ABOUT PHP
datetime.modify
DATETIME.MODIFY(3) 1 DATETIME.MODIFY(3)DateTime::modify - Alters the timestamp
Object oriented style
SYNOPSIS
public DateTime DateTime::modify (string $modify)
DESCRIPTION
Procedural style
DateTime date_modify (DateTime $object, string $modify)
Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3).
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $modify
-A date/time string. Valid formats are explained in Date and Time Formats.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.6 | |
| | |
| | Absolute date/time statements now take effect. |
| | Previously, only relative parts were used. |
| | |
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.modify(3) example
Object oriented style
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2006-12-12');
date_modify($date, '+1 day');
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2006-12-13
Example #2
Beware when adding or subtracting months
<?php
$date = new DateTime('2000-12-31');
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
SEE ALSO strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes-
tamp(3).
PHP Documentation Group DATETIME.MODIFY(3)