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Top Forums Shell Programming and Scripting How to Pass filename to AWK in bash script Post 302684453 by jim mcnamara on Thursday 9th of August 2012 03:08:48 PM
Old 08-09-2012
Try using FILENAME with a little restructuring:
Code:
excludefile=somefile.dat
infile=anotherfile.dat

awk v- in="$infile" -v exf="$excludefile" '
       FILENAME==exf 
         {n=0;while (getline < "$excludefile" > 0){ex[n]=$0;n++}}  
       FILENAME==in  
       {for(var in ex)
       {print  var "-" ex[var] $0 ;i++}}' $excludefile $infile

If you are totaly into one-liners you can one-line this if you want.
This User Gave Thanks to jim mcnamara For This Post:
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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