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Operating Systems Solaris Which gives the correct swap space top/vmstat ? Post 302683889 by chidori on Wednesday 8th of August 2012 09:18:55 PM
Old 08-08-2012
Which gives the correct swap space top/vmstat ?

Code:
last pid: 29502;  load avg:  21.8,  20.7,  20.4;       up 8+08:49:09 
763 processes: 589 sleeping, 9 running, 160 zombie, 5 on cpu
CPU states:  0.0% idle, 28.2% user, 71.8% kernel,  0.0% iowait,  0.0% swap
Memory: 32G phys mem, 2042M free mem, 8198M total swap, 8020M free swap

Code:
 
kthr      memory            page            disk          faults      cpu
 r b w   swap  free  re  mf pi po fr de sr m0 m1 m3 m4   in   sy   cs us sy id
 14 0 0 2278240 3160744 560 2312 2664 143 143 0 1 0 0 0 0 1498 2947 3988 34 65 1
 17 0 0 772472 2087800 182 2353 8 0 0 0  0  0  0  0  0  808 30069 3288 24 76 0
 9 0 0 630128 2086600 250 2937 22 0 0 0  0  0  0  0  0  912 25393 3059 22 78 0
 17 0 0 647680 2085688 250 2951 24 0 0 0 0  0  0  0  0  818 28944 2987 22 78 0
 15 0 0 1414032 2084080 305 2937 8 0 0 0 0  0  0  0  0  895 30802 3400 23 77 0

top command gives 8G swap space and vmstat shows 1.3G free

Please help me in understanding this
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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