Hi there,
When I run top on my machine it says I have 497M swap space in use, and 380M swap space free,
but I have only allocated 512M swap space to the machine!!!!
Does anyone know how swap used is calculated in the top command?
Thanks... (1 Reply)
Hi there,
I´m trying to get the information of vmstat & top in two different logfiles.
That not that difficult.
vmstat 30 >> myfile.log
top >> myfile2.log
But I also like to include a timestamp every 30 sec to be sure from what date the logs are.
For the Top command I were able to... (2 Replies)
Hi
I have checked the output of top command in which there is a difference shown between the swap of top command for a process with total swap memory usage of the top command.
Swap usage of process is higher than the total swap memory usage.
top - 18:28:21 up 7:13, 5 users, load... (2 Replies)
Hi all,
I have a server running an Oracle database that is part of a Solaris M5000 container. Presumably this is referred to as a zone within a cluster, not sure if I get the terminology right.
Anyway, a third-party manages the zone and unfortunately is not "helpful/friendly" to assist me on... (1 Reply)
Hi,
OS = Solaris 5.10
I need some guidance on interpreting vmstat to confirm whether my server is swapping or not. Can anyone please advise whether the column to check on the vmstat output is the pi column, does higher pi values means the server is swapping or am having swapping issues?
... (1 Reply)
Hi all,
OS = Solaris 5.10
Without using top, can anyone please advise how to get the current swap space that is assigned to a sub-zone that is part of the Solaris zone? Some of the servers does not have the top command and I do not have access to run zone level commands either like zonecfg... (3 Replies)
Hi,
i have done a blunder here, i increased the swap space on Xen5.6 server machine using below steps :-
1056 dd if=/dev/zero of=/root/myswapfile bs=1M count=1024
1057 ls -l /root/myswapfile
1058 chmod 600 /root/myswapfile
1059 mkswap /root/myswapfile
1060 swapon /root/myswapfile
... (1 Reply)
RHEL 5.4
Our Linux machine seemed to be running slow. So, I ran the top and vmstat commands.
Question1.
I can see the process 11517 consuming 100% CPU . But that just means that this process totally utilizes one of the cores in a mult-core CPU. Right ? This machine apparently has two... (2 Replies)
Discussion started by: kraljic
2 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)