My OS is solaris 64 bit 10, I have many files in a logs directory where we recive 40-50 logs every day. i have last 20 days file present in this directory. I want to move each day file to a particulaar directory whose name is appended with the date of file.
eg
then create a directory for old files of 31-jul RIO_31-Jul-2012 and move them and like wise for 01-aug files.
I have written a scripts which is running fine for current date but i don't know how t modify it to accomdate old date.
---------- Post updated at 10:55 AM ---------- Previous update was at 10:54 AM ----------
My scripts is as below
Thanks
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Please use code tags when posting data and code samples!
Last edited by vgersh99; 08-01-2012 at 01:15 PM..
Reason: code tags, please!
I am trying to load a group of files and their last dates modified into a text file that will in turn be used with SQL*Loader to load these files into Oracle. I am using a *.ksh script. I am getting the name of the file in by using the following:
for file_ext in 'cat loaddir.ext';
do
find... (2 Replies)
I need to extract the date part from the file name (20080221 in this ex) and compare it with the current date and delete it, if it is a past date.
$file = exp_ABCD4_T-2584780_upto_20080221.dmp.Z
really appreciate any help.
thanks
mkneni (4 Replies)
Hi,
I am new bie to Unix. Might be a simple question I am asking.
I want to find the last modified time of a file and find the difference between the currrent time and the last modified time. Appreciate, if someone can throw some light on what commands can be used.
Cheers,
James (2 Replies)
Hello gurus,
I am hoping someone can help me with the required code/script to make this work. I have the following file with records starting at line 4:
NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~... (4 Replies)
Hi there!
I was wondering if someone could help me with the following:
I'm trying to find all files within a directory which have been modified since midnight of the current date.
Any help would be appreciated.
Thank you kindly. (6 Replies)
I'm using a script that I need to get a file's "last modified date" in a format like 01:51:14 PM. We are running on AIX 6.1.0.0. I can't seem to find the right command parameters. Help! (4 Replies)
Hi,
Am performing a find based on filename and result can contain multiple files being found
Let's say my find command is
find /Archive -f -name 12345.pdf
and result of find command is
/Archive/Folder A/12345.pdf
/Archive/Folder B/12345.pdf
please note white space in folder names
I... (2 Replies)
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
We want to call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below:
abc.txt
------------------
Code:
line1
line2
line3
$$EDWS_DATE_INSERT=08-27-2019
line4
$$EDWS_PREV_DATE_INSERT=08-26-2019
I am trying to write a... (3 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)