07-31-2012
Passing a string variable from Unix to Sql Plus
Hi Guys,
I am trying to pass a string variable from Unix shell script to sqlplus as a parameter.
I have tried using single quotes with the variable name but it does not work. Please help me with it.
I am using BASH.
My code:
Quote:
for line in $(head -$to_line table_list.txt | tail -$no_lines)
do
echo $line
sqlplus -S -L $from_db >> $sqlscript <<EndSQL1
SELECT LTRIM(MAX(SYS_CONNECT_BY_PATH (col_name,', ')),',') FROM (
SELECT column_id,CASE WHEN data_type LIKE 'TIMESTAMP%' THEN 'TRUNC(' ||column_name || ')'
ELSE column_name END col_name FROM (SELECT * FROM all_tab_columns
WHERE table_name= '$line'
) ORDER BY column_id ) START WITH column_id = 1 CONNECT BY PRIOR column_id = column_id -1;
exit
EndSQL1
Your help is much appreciated.
Thanks,
shil
Last edited by infintenumbers; 07-31-2012 at 05:34 PM..
Reason: Minor typo in code tags.
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LEARN ABOUT PHP
escapeshellarg
ESCAPESHELLARG(3) 1 ESCAPESHELLARG(3)
escapeshellarg - Escape a string to be used as a shell argument
SYNOPSIS
string escapeshellarg (string $arg)
DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly
to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to
shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator.
On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string.
PARAMETERS
o $arg
- The argument that will be escaped.
RETURN VALUES
The escaped string.
EXAMPLES
Example #1
escapeshellarg(3) example
<?php
system('ls '.escapeshellarg($dir));
?>
SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator.
PHP Documentation Group ESCAPESHELLARG(3)