07-31-2012
I don't think 'type=3' makes sense inside a select like that. I think you might be able to do '3 as type'.
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LEARN ABOUT PHP
mysql_db_query
MYSQL_DB_QUERY(3) 1 MYSQL_DB_QUERY(3)
mysql_db_query - Selects a database and executes a query on it
SYNOPSIS
Warning
This function was deprecated in PHP 5.3.0, and will be removed in the future, along with the entirety of the original MySQL exten-
sion. Instead, the MySQLi or PDO_MySQL extension should be used. See also MySQL: choosing an API guide and related FAQ for more
information. Alternatives to this function include:
omysqli_select_db(3) then the query
o PDO::__construct
resource mysql_db_query (string $database, string $query, [resource $link_identifier = NULL])
DESCRIPTION
mysql_db_query(3) selects a database, and executes a query on it.
o $database
- The name of the database that will be selected.
o $query
- The MySQL query. Data inside the query should be properly escaped.
o $
link_identifier -The MySQL connection. If the link identifier is not specified, the last link opened by mysql_connect(3) is
assumed. If no such link is found, it will try to create one as if mysql_connect(3) was called with no arguments. If no connection
is found or established, an E_WARNING level error is generated.
Returns a positive MySQL result resource to the query result, or FALSE on error. The function also returns TRUE/ FALSE for INSERT/ UPDATE/
DELETE queries to indicate success/failure.
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | This function now throws an E_DEPRECATED notice. |
| | |
+--------+---------------------------------------------------+
Example #1
mysql_db_query(3) alternative example
<?php
if (!$link = mysql_connect('mysql_host', 'mysql_user', 'mysql_password')) {
echo 'Could not connect to mysql';
exit;
}
if (!mysql_select_db('mysql_dbname', $link)) {
echo 'Could not select database';
exit;
}
$sql = 'SELECT foo FROM bar WHERE id = 42';
$result = mysql_query($sql, $link);
if (!$result) {
echo "DB Error, could not query the database
";
echo 'MySQL Error: ' . mysql_error();
exit;
}
while ($row = mysql_fetch_assoc($result)) {
echo $row['foo'];
}
mysql_free_result($result);
?>
Note
Be aware that this function does NOT switch back to the database you were connected before. In other words, you can't use this
function to temporarily run a sql query on another database, you would have to manually switch back. Users are strongly encouraged
to use the database.table syntax in their sql queries or mysql_select_db(3) instead of this function.
mysql_query(3), mysql_select_db(3).
PHP Documentation Group MYSQL_DB_QUERY(3)