On Unix, it is easy to get those lines that match a pattern, by
grep pattern file
or those lines that do not, by
grep -v pattern file
but I am editing a file on Windows with Ultraedit.
Ultraedit support regular expression based search and replace.
I can delete all the lines that match a... (1 Reply)
I am really need help with the regular expression in SED. From input file, I need to extract lines that have the port number (sport or dport) as defined. The input file is something like this
time=1209515280-1209515340 dst=192.168.133.202 src=208.70.8.23 bytes=2472 proto=6 sport=80 dport=1447... (6 Replies)
Hi there,
I need help about using sed. Iam using sed to delete and print lines that match the port number as listed in sedfile. I am using -d and -p command for delete match port and print them respectively. However, the output is not synchonize where the total deleted lines is not similar with... (3 Replies)
Hi All,
Below is my requirement. Whatever coming in between ' ', needs to delete.
Input File Contents:
==============
This is nice 'boy'
This 'is
bad
boy.' Got it
Expected Output
===========
This is nice
This
Got it (4 Replies)
Hello sed gurus. I am using ksh on Sun and have a file created by concatenating several other files. All files contain header rows. I just need to keep the first occurrence and remove all other header rows.
header for file
1111
2222
3333
header for file
1111
2222
3333
header for file... (8 Replies)
Hello Experts , require help . See below output:
File inputs
------------------------------------------
Server Host = mike
id rl images allocated last updated density
vimages expiration last read <------- STATUS ------->... (4 Replies)
The intended result should be :
PDF converters
'empty line'
gpdftext and pdftotext?xml version="1.0"?>
xml:space="preserve"><note-content version="0.1" xmlns:/tomboy/link" xmlns:size="http://beatniksoftware.com/tomboy/size">PDF converters
gpdftext and pdftotext</note-content>... (9 Replies)
I have a file
Line 1 a
Line 22
Line 33
Line 1 b
Line 22
Line 1 c
Line 4
Line 5
I want to delete all lines before last occurrence of a line which contains something which is defined in a variable. Say a variable var contains 'Line 1', then I need the following in the output.
... (21 Replies)
Discussion started by: Soham
21 Replies
LEARN ABOUT PLAN9
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for a pattern
SYNOPSIS
grep [ option ... ] pattern [ file ... ]
DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as
defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output.
The options are
-c Print only a count of matching lines.
-h Do not print file name tags (headers) with output lines.
-i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre-
tation. Matched lines are printed in their original form.
-l (ell) Print the names of files with selected lines; don't print the lines.
-L Print the names of files with no selected lines; the converse of -l.
-n Mark each printed line with its line number counted in its file.
-s Produce no output, but return status.
-v Reverse: print lines that do not match the pattern.
Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name
argument.)
Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in
single quotes '...'.
SOURCE
/sys/src/cmd/grep.c
SEE ALSO ed(1), awk(1), sed(1), sam(1), regexp(6)DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs.
GREP(1)