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Top Forums Shell Programming and Scripting cant get variable outside "while" in ssh Post 302676509 by sanantonio7777 on Tuesday 24th of July 2012 05:13:09 PM
Old 07-24-2012
Code:
awk  '/<iframe /{p=1} /<\/iframe/{p=0; next}!p'

this remove <iframe></iframe> tags from $result_get or inputfile

next I count the words in every line
and I want to get all the lines with more than 20 words
in one var outside the loop
thats all...
I will change the pipe .. thank you !

Last edited by sanantonio7777; 07-24-2012 at 06:58 PM..
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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