in csh
set x = "/home/usr/dir1/file1"
if i do:
echo $x | awk -F\/ '{print $NF}'
will result to:
"file1"
how do i invert the output to:
"/home/usr/dir1"
:confused: (2 Replies)
I'm hoping someone can help me on this. I have a data file that greatly simplified might look like this:
sec;src;dst;proto
421;10.10.10.1;10.10.10.2;tcp
426;10.10.10.3;10.10.10.4;udp
442;10.10.10.5;10.10.10.6;tcp
sec;src;fac;dst;proto
521;10.10.10.1;ab;10.10.10.2;tcp... (3 Replies)
(extract from SQL binlog file...)
# at 4960
#080801 14:35:31 server id 4 end_log_pos 195 Query thread_id=63121426 exec_time=0 error_code=0
use d_jds;
SET TIMESTAMP=1217581531;
UPDATE bid_details set bidding = 3170.37 ,deduction=if((3170.37 < 37.43),0,deduction)
where... (3 Replies)
Hello,
I had posted earlier about printing fields using AWK, but now I have a slightly different problem. I have text files in the format:
1*2,3,4,5
and wish to print the first, third, and fifth fields, including the asterisk and commas. In other words, after filtering it should look... (1 Reply)
I am trying to get folder names that contain only numbers.
Can someone explain why following command is printing 'total 450' as part of output..
$> ls -lt | awk '$9 ~ /^*$/' | more
total 450
drwxr-x--x 3 user1 group1 512 Mar 9 2008 329227163
drwxr-x--x 3 user1 group1 ... (17 Replies)
Dear all,
I have been trying to print an entire field, if the first line of the field is matching.
For example, my input looks something like this.
aaa ddd zzz
123 987 126
24 0.650 985
354 9864 0.32
0.333 4324 000
I am looking for a pattern,... (5 Replies)
I have a need to print nth field based on the parameter passed. Suppose I have 3 fields in a file, passing 1 to the function should print 1st field and so on.
I have attempted below function but this throws an error due to incorrect awk syntax.
function calcmaxlen
{
FIELDMAXLEN=0
... (5 Replies)
Hi folks,
I am very new to awk. I have what is probably a very simple question. I'm trying to get the max value of column 1, but also print column 2. My data looks like this:
0.044|2000-02-03 14:00:00
5.23|2000-02-03 05:45:00
5.26|2000-02-03 11:15:00
0|2000-02-01 18:30:00
So in this case... (2 Replies)
I apologize in advance, but I continue to have trouble searching for matches between two files and then printing portions of each to output in awk and would very much appreciate some help.
I have data as follows:
File1
PS012,002 PRQ 0 1 1 17 1 0 -1 3 2 1 2 -1 ... (7 Replies)
Hi,
Sure it's an easy one, but it drives me insane.
input ("|" separated):
1|A,B,C,A
2|A,D,D
3|A,B,B
I would like to count the occurence of each capital letters in $2 across the entire file, knowing that duplicates in each record count as 1.
I am trying to get this output... (5 Replies)
Discussion started by: beca123456
5 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)