06-20-2012
Unix Log out time
Hi,
Is there a way to find out the logout date for a user who has been logged in to the system for more than 1 day. For example, the below user as indicated by the "last" command had logged into the system on Mar 8 and he has been online for 2 days and 6:53 hour:min. So basically, he logged out from the system on Mar 10. Is there a way to calculate this in Perl? or any other command that gives the logout date as well.?
dpryor console Wed Mar 8 10:47 - 17:41 (2+06:53)
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rwho(1) General Commands Manual rwho(1)
NAME
rwho - show who is logged in on local machines
SYNOPSIS
DESCRIPTION
produces output similar to the output of the HP-UX command for all machines on the local network that are running the daemon (see who(1)
and rwhod(1M)). If has not received a report from a machine for 11 minutes, assumes the machine is down and does not report users last
known to be logged into that machine.
output line has fields for the name of the user, the name of the machine, the user's terminal line, the time the user logged in, and the
amount of time the user has been idle. Idle time is shown as:
If a user has not typed to the system for a minute or more, reports this as idle time. If a user has not typed to the system for an hour
or more, the user is omitted from output unless the flag is given.
An example output line from would look similar to:
This output line could be interpreted as is logged into and his terminal line is has been logged on since September 12 at 13:28 (1:28
p.m.). has not typed anything into for 11 minutes.
WARNINGS
output becomes unwieldy when the number of users for each machine on the local network running becomes large. One line of output occurs
for each user on each machine on the local network that is running
AUTHOR
was developed by the University of California, Berkeley.
FILES
Information about other machines.
SEE ALSO
ruptime(1), rusers(1), rwhod(1M).
rwho(1)