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Full Discussion: sed replace
Top Forums Shell Programming and Scripting sed replace Post 302658237 by midhun19 on Tuesday 19th of June 2012 04:37:29 AM
Old 06-19-2012
sed replace

Hi,

i have a file as give below

Code:
>cat sample_file
param1 val1 2012-06-19

##there can be one or more space after 2012-06-19 in the above file

i want to replace val1 with a with value passed through a variable...
below is the command i tried
Code:
>parval='param1 val2'
>par1=param1
>sed "s/$par1 ..* /$parval /g" < sample_file

param1 val2

ie, the whole line in the sample file is replaced (the date is removed) but i want only the param1 val1 to be replaced with the parval variable value

can anyone help me with a suitable sed command for this requirement
 

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GSL-RANDIST(1)						      General Commands Manual						    GSL-RANDIST(1)

NAME
gsl-randist - generate random samples from various distributions SYNOPSYS
gsl-randist seed n DIST param1 param2 [..] DESCRIPTION
gsl-randist is a demonstration program for the GNU Scientific Library. It generates n random samples from the distribution DIST using the distribution parameters param1, param2, ... EXAMPLE
Here is an example. We generate 10000 random samples from a Cauchy distribution with a width of 30 and histogram them over the range -100 to 100, using 200 bins. gsl-randist 0 10000 cauchy 30 | gsl-histogram -100 100 200 > histogram.dat A plot of the resulting histogram will show the familiar shape of the Cauchy distribution with fluctuations caused by the finite sample size. awk '{print $1, $3 ; print $2, $3}' histogram.dat | graph -T X SEE ALSO
gsl(3), gsl-histogram(1). AUTHOR
gsl-randist was written by James Theiler and Brian Gough. Copyright 1996-2000; for copying conditions see the GNU General Public Licence. This manual page was added by the Dirk Eddelbuettel <edd@debian.org>, the Debian GNU/Linux maintainer for GSL. GNU
GSL-RANDIST(1)
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