i doubt that this works. correct should be (notice the spaces):
If i read the script source correctly the variables in question are both integers. You could also use integer comparation then (see man test for a complete description of available options)
I am not sure if this works or not, but in any case this will definitely be correct (again, notice the spaces, they are necessary):
A further tip: do NOT USE BACKTICKS! Backticks are an ancient device, which has some (quite intricate) shortcomings and are supported only for backwards compatibility. You use something like:
and want the output of "command" to become the variables content. Use
for this purpose, which has none of the shortcomings and all of the features of the above syntax.
One last tip: before using *any* variable, declare it at the beginning of your script. This offers the opportunity to document the variables contents, which helps greatly in maintaining your scripts, as well as to make sure all necessary variables are initialized with sensible values:
I've noted that in order to use commands like ifconfig, I have to prefix the commands with the directory.
/etc/profile shows that the paths should be part of the PATH environment variable; any idea where the bug is?
:confused:
# /etc/profile
# System wide environment and startup... (1 Reply)
In a bash script I've set a variable that is the directory name of where an executable lives.
the_dir=`dirname $which myscript`
which equates to something like "/path/to/dir/bin"
I need to cut that down to remove the "bin" so I now have "/path/to/dir/".
This sounds easy but as a... (2 Replies)
Hi all,
if for example I had a variable containing the string 'hello', is the any way I can output, for example, the e and the 2nd l based on their position in the string not their character (in this case 2 and 4)?
any general pointers in the right direction will be much appreciated, at... (3 Replies)
Hello,
I have a paramter $param consisting just of two literals and want to split it into two parameters, so I can combine it to a new parameter <char1><string><char2>, but the following code didn't work:
tmp_PARAM_1=cut -c1 $PARAM
tmp_PARAM_2=cut -c2 $PARAM... (2 Replies)
Hi ,I am trying to assign string to variable ,but it doesn't work
Also could you show me different ways to use grep,(I am trying to get the first,second and first column form file,and I am counting the chars)
let name=`grep "$id" product | cut -c6-20` (25 Replies)
Hi
I am very new to using BASH, but I have a problem with a piece of script that I have been working on. Basically the script goes through a mailbox file looking at particular aspects of the file, for example how many spamwords there are email address etc. It does this pretty well except for an... (13 Replies)
Hello,
Why is this not working in a script?
files="test.fsa"
echo $files
for file in $files
do
if
then
echo "$file does not exist."
fi
run a command
done
I get an error saying (3 Replies)
Hi,
I've been stuck for several days on this. Using grep on a command line, I can use quotes, eg...
grep 'pattern of several words' filename
I want to do this in my bash script. In my script I have captured the several command line arguments (eg arg1 arg2) into a variable:
variable=$@
I... (2 Replies)
I'm trying to write a basic bash script that takes input you give (what directory, if any, what name, if any ....) and passes the information to find.
I'm trying to just create a string with all variables and then pass it to find. So far I have this extremely simple:
#!/bin/bash -f
... (2 Replies)
Hi All;
I have 2 variable let's say $A and $B. These are actually some remotely executed command outputs. I captured these values in my local variables. Here is my problem. When I try to do some arithmetic operation with these variables, I receive an error message. Neither expr nor typeset -i... (3 Replies)