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Top Forums Shell Programming and Scripting Need help with AWK code using xargs Post 302649243 by Subu1987 on Thursday 31st of May 2012 05:23:50 AM
Old 05-31-2012
Hi birei and sdf,

Thank you for your contributions. Unfortunately, these did not resolve my problem. Smilie Perhaps I was not able to explain my requirement correctly. Stripping the name was not an issue for me. The issue was names with single-quotes in them, like O'Bar, Foo. In such a case, the single-qoute in the name would be paired with the single-qoute at the beginning of the awk program, causing rest of the awk program to be ignored, and hence, a syntax-error. So, the single-qoute in the name had to be escaped, before it was passed on to the awk program. I achieved this by using the following code --
Code:
nameVar=`grep -w ^"NAME:" inputFile.txt | sed -e "s/\'/\\\'/g" | awk -F" " '{ for ( i = 2; i++; i <= NF) {print $i} }' | xargs`

 

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