I have a static date in a YYYYMMDD format; and I want get the date 2 years in the past and 2 years in the future.
I was only able to research on dates that are current and not on static dates wherein I can have it set and just changing it when I want.
Please help...
Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.
Ramesh (1 Reply)
I have looked through the forums and found many date / time manipulation tools, but cannot seem to find something that fits my needs for the following.
I have a log file with date time stamps like this:
Jun 21 17:21:52
Jun 21 17:24:56
Jun 21 17:27:59
Jun 21 17:31:03
Jun 21 17:34:07
Jun... (0 Replies)
how can we add or subtract days from the output of date command in unix...
like if i want to subtract a day from the result of date command like this..
v_date=`date +%Y%m%d`
this wud give me 20080519
now i want to subtract one day from this.. so tht it wud give me 20080518..
how do i do... (1 Reply)
Hi,
I'm writing an batch file to create report
In the batch file iam passing two arguments:startdate and finishdate
Ex: startdate=07-sep-2009 finishdate=07-sep-2011
I need to have script that takes command line argument as input and gives me out currentdate last year and current date... (2 Replies)
$beginDate = substr(DateCalc("today", "-7Days"),0,8);
This fetches the date 7 days back
Can I fetch the date before 7 years from todays date in Perl using same syntax
Use code tags, see PM. (3 Replies)
Hi All,
I am getting a date from environment variable and want to do some processing by subtracting 2 months from the date passed through the environment variable.
I am trying the following syntax :
date_var=2014-08-31
date_2M_ago='$date_var+"%d%m%y" --$date_var="2 months ago" '... (3 Replies)
Hi Folks,
I have a file with 2 columns TAB delimited and I want to add '1' to the first column and subtract '-1' from the second column.
What I have tried so far is;
awk -F"\t" '{ $1-=1;$2+=1}1' OFS='\t' file
File
0623 0623
0624 0624
0643 0643
1059 1037
1037 1037
1038 1038... (2 Replies)
Hi All,
I have a CSV file which is as below. Basically I need to take the year column in it and find if the year is >= 20152 . If that is then I should subtract all values by 6. In the below example in description I am having number mentioned as YYWW so I need to subtract those by -5. Whereever... (8 Replies)
Discussion started by: arunkumar_mca
8 Replies
LEARN ABOUT CENTOS
pmdate
PMDATE(1) General Commands Manual PMDATE(1)NAME
pmdate - display an offset date
SYNOPSIS
pmdate [ offset ... ] format
DESCRIPTION
pmdate displays the current date and/or time, with an optional offset.
An offset is specified with a leading sign (``+'' or ``-''), followed by an integer value, followed by one of the following ``scale'' spec-
ifiers;
S seconds
M minutes
H hours
d days
m months
y years
The output format follows the same rules as for date(1) and strftime(3).
For example, the following will display the date a week ago as DDMMYYYY;
pmdate -7d %d%m%Y
PCP ENVIRONMENT
Environment variables with the prefix PCP_ are used to parameterize the file and directory names used by PCP. On each installation, the
file /etc/pcp.conf contains the local values for these variables. The $PCP_CONF variable may be used to specify an alternative configura-
tion file, as described in pcp.conf(5).
SEE ALSO date(1), strftime(3), pcp.conf(5) and pcp.env(5).
Performance Co-Pilot PCP PMDATE(1)