I need to delete stats on every 2nd Sunday and I've try the following codes but unfortunately it didn't work. I'll really appreciate as always for your help. I'm on FreeBSD 8.2-STABLE.
Hi All,
I have to kick off a script on every Monday to get some data from database for last week (Sunday thru Saturday).
If its Monday (12/12/2005)
Begin date will be Sunday - 12/4/2005
End date will be Saturday - 12/10/2005
The script might not kick off on some Mondays.
So my... (2 Replies)
Dear all
How can I schedule the cronjob to be run sometime at every first Sunday at every month? I have the edit the cronjob every month now, thanks (2 Replies)
Hi ,
I have a date parameter passed in YYYYMMDD format , how can I check whether it is Sat or Sun on Solaris box , as we can do the same easily on linux box by using date -d YYYYMMDD '+a' .
Any pointres will be really helpful . (5 Replies)
Hi Am using Unix Ksh
I have a two date input as
DATE1=02/12/2012
DATE2=30/12/2012
I Need the output as only sunday date
02/12/2012
09/12/2012
16/12/2012
23/12/2012
30/12/2012
can anyone pls help me..
thanks in advance... (2 Replies)
Hi Am using unix Ksh
I have the two dates
DATE1=01/01/2013
DATE2=11/02/2013
In this two dates i need the output as count of sunday
sunday=6
Can anyone help me pls!!! (1 Reply)
Hi,
I want to get the second Sunday of march in any year, I have tried below command but it is not giving me the correct output
i_year=`date +%Y`
cal -m 03 $i_year | sed '/^$/d' |head -4 |tail -1|rev | cut -c1`
This is returning me 0 , where as I want 10.
Can you please help
Thanks (5 Replies)
Hi,
Please can someone help me in getting first sunday date of a month.
i_year=`date +%Y`
ny_first_sun_nov=`cal 10 $i_year | sed '/^$/d' |head -3 |tail -1| rev | cut -c1`
This works good if the first sunday has a value but not if it is blank and first sunday falls on second week.
... (17 Replies)
Hi All,
Can you please let me know how to get the yesterday's date of the given date if the given date is Sunday?
I can't use GNU. I have the code to get the yesterday's date based on the system date.
Thanks (5 Replies)
Hi,
Actually scheduled my test scripts on test severs as shown below. They are supposed to run on 3rd sunday of every month.
Unfortunately it ran on 2nd sunday of the month (suspecting that it will run every sunday). I am sorry if I miss something. Could you please let me know if I did any... (1 Reply)
Discussion started by: System Admin 77
1 Replies
LEARN ABOUT PLAN9
cron
CRON(8) System Manager's Manual CRON(8)NAME
cron - clock daemon
SYNOPSIS
auth/cron [-c]
DESCRIPTION
Cron executes commands at specified dates and times according to instructions in the files /cron/user/cron. It runs only on an authentica-
tion server. Option -c causes cron to create /cron/user and /cron/user/cron for the current user; it can be run from any Plan 9 machine.
Blank lines and lines beginning with # in these files are ignored. Entries are lines with fields
minute hour day month weekday host command
Command is a string, which may contain spaces, that is passed to an rc(1) running on host for execution. The first five fields are integer
patterns for
minute 0-59
hour 0-23
day of month 1-31
month of year 1-12
day of week 0-6; 0=Sunday
The syntax for these patterns is
time : '*'
| range
range : number
| number '-' number
| range ',' range
Each number must be in the appropriate range. Hyphens specify inclusive ranges of valid times; commas specify lists of valid time ranges.
To run the job, cron calls host and authenticates remote execution, equivalent to running rx host command (see con(1)). The user's profile
is run with $service set to rx.
Cron is not a reliable service. It skips commands if it cannot reach host within two minutes, or if the cron daemon is not running at the
appropriate time.
EXAMPLES
Here is the job that mails system news.
% cat /cron/upas/cron
# send system news
15 8-17, 21 *** helix /mail/lib/mailnews
%
SOURCE
/sys/src/cmd/auth/cron.c
SEE ALSO con(1), rc(1)CRON(8)