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passing command arguments from a file?
Post 302637129 by vegatripy on Tuesday 8th of May 2012 11:20:40 AM
05-08-2012
passing command arguments from a file?
Hi
Im trying to run zip shell command from an Oracle job, but this has limitations.
This should take a few of explanaition,..
Oracle allows me to execute a command and then I can set up a fixed number of arguments. Ex: (summarizing in something like..):
But the problem comes when I need an indetermined number of arguments, and cannot use spaces in arguments definitions.
So I was wondering in using something like
.
Then I've been wondering if I can write the arguments in a plain text file and then pass arguments from that file.
It must be something like..
How it should be?
I have a lazy remember from my student past that in bash that you could do this with '<<<', like:
Any idea?
Regards
Im trying to run zip shell command from an Oracle job, but this has limitations.
This should take a few of explanaition,..
Oracle allows me to execute a command and then I can set up a fixed number of arguments. Ex: (summarizing in something like..):
JOB DEFINITIONThen oracle execute "zip -j foo.zip foo01 foo02"
job_name: test
job_action: /usr/bin/zip
job_arguments: 4
and then:
JOB test ARGUMENTS
ARGUMENT 1: -j
ARGUMENT 2: foo.zip
ARGUMENT 3: foo01
ARGUMENT 4: foo02
But the problem comes when I need an indetermined number of arguments, and cannot use spaces in arguments definitions.
So I was wondering in using something like
JOB DEFINITIONThis *should* work, but, somehow, not
job_name: test
job_action: /bin/sh
job_arguments: 2
and then:
JOB test ARGUMENTS
ARGUMENT 1: -c
ARGUMENT 2: "/usr/bin/zip -j foo.zip foo01 foo02 andwhateverstringiwanttoconcattothis"
. Then I've been wondering if I can write the arguments in a plain text file and then pass arguments from that file.
It must be something like..
Is this possible?
$ cat filename-with-args-inside
-j foo.zip foo01 foo02
$ /usr/bin/zip [SHELLOPERATORORWHATEVER] filename-with-args-inside
How it should be?
I have a lazy remember from my student past that in bash that you could do this with '<<<', like:
..But it doesnt work
$ /usr/bin/zip <<<filename-with-args-inside
Any idea?
Regards
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Last edited by vbe; 05-08-2012 at 01:05 PM..
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LEARN ABOUT CENTOS
zip_replace
ZIP_ADD(3) Library Functions Manual ZIP_ADD(3) NAME
zip_add , - .Nm zip_replace add file to zip archive or replace file in zip archive LIBRARY
libzip (-lzip) SYNOPSIS
#include <zip.h> zip_int64_t zip_add(struct zip *archive, const char *name); "struct zip_source *source" int zip_replace(struct zip *archive, zip_uint64_t index); "struct zip_source *source" DESCRIPTION
The function zip_add adds a file to a zip archive, while zip_replace replaces an existing file in a zip archive. The argument archive specifies the zip archive to which the file should be added. name is the file's name in the zip archive (for zip_add ), while index speci- fies which file should be replaced (for zip_replace ). The data is obtained from the source argument. See the zip_source_* functions cited in SEE ALSO. RETURN VALUES
Upon successful completion, zip_add returns the index of the new file in the archive, and zip_replace returns 0. Otherwise, -1 is returned and the error code in archive is set to indicate the error. EXAMPLES
struct zip_source *s; if ((s=zip_source_buffer(archive, buffer, len)) == NULL || zip_add(archive, name, s) 0) { zip_source_free(s); printf("error adding file: %s0, zip_strerror(archive)); } ERRORS
zip_add and zip_replace fail if: [ZIP_ER_EXISTS] There is already a file called name in the archive. (Only applies to zip_add ). [ZIP_ER_INVAL] source or name are NULL, or index is invalid. [ZIP_ER_MEMORY] Required memory could not be allocated. SEE ALSO
libzip(3), zip_source_file(3), zip_source_filep(3), zip_source_function(3), zip_source_zip(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH March 10, 2009 ZIP_ADD(3)