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Top Forums Programming Why do I receive Program received signal SIGABRT, Aborted? Post 302634043 by Corona688 on Wednesday 2nd of May 2012 09:22:55 PM
Old 05-02-2012
We'll need to see a whole lot more than that... We can't see any of the code which defines any of that, so any of it could be crashing for any reason.

Try printing out the pointers with fprintf(stderr, "%p", pointer); to see if you're getting bad values creeping into your list.
 

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ABORT(3)						     Linux Programmer's Manual							  ABORT(3)

NAME
abort - cause abnormal process termination SYNOPSIS
#include <stdlib.h> void abort(void); DESCRIPTION
The abort() first unblocks the SIGABRT signal, and then raises that signal for the calling process. This results in the abnormal termina- tion of the process unless the SIGABRT signal is caught and the signal handler does not return (see longjmp(3)). If the abort() function causes process termination, all open streams are closed and flushed. If the SIGABRT signal is ignored, or caught by a handler that returns, the abort() function will still terminate the process. It does this by restoring the default disposition for SIGABRT and then raising the signal for a second time. RETURN VALUE
The abort() function never returns. CONFORMING TO
SVr4, POSIX.1-2001, 4.3BSD, C89, C99. SEE ALSO
gdb(1), sigaction(2), exit(3), longjmp(3), raise(3) COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. GNU
2007-12-15 ABORT(3)
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