i had a code where in user will enter a date in yyyymmdd format.. i didnt use any validation for the date and now the problem is if a user enters date instead of month after year it is proceeding with the code..
like if the date is
and if the user enters
it should not proceed!
I would like to know how I could get a yesterday date in yyyymmdd e.g. today is 20011109, and I would like to get 20011108. Thank you!:confused: (2 Replies)
I have a file with some date columns in MM/DD/YYYY format:
SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458|
And I want to convert the date format to:
... (5 Replies)
In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.
Thanks. (8 Replies)
Hi All,
I am learning PERL for one of the projects, and in one of these scripts, I read a flat text file and print in the terminal.
The problem is, the text file has a date field. The format is yyyymmdd. I need to display this as dd-mon-yyyy.
Any ideas to do this? Thanks a lot for the... (9 Replies)
My requirement is:- there will be files at a location each day with the date format DDMMYYYY.
Novawise_Activity_Call_Notes_04022013.txt
Novawise_Activity_Inbound_04022013.txt
Novawise_Activity_Inbound_05022013.txt
Novawise_Activity_Call_Notes_05022013.txt... (8 Replies)
Hi All,
I have line
,A,FDRM0002,12/21/2017,,0.961751583,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
it contains date in mm/dd/yyyy format i want to change this to yyyymmdd format using perl.
Use code tags, thanks. (8 Replies)
Discussion started by: vishal0746
8 Replies
LEARN ABOUT PHP
datetime.setisodate
DATETIME.SETISODATE(3) 1 DATETIME.SETISODATE(3)DateTime::setISODate - Sets the ISO date
Object oriented style
SYNOPSIS
public DateTime DateTime::setISODate (int $year, int $week, [int $day = 1])
DESCRIPTION
Procedural style
DateTime date_isodate_set (DateTime $object, int $year, int $week, [int $day = 1])
Set a date according to the ISO 8601 standard - using weeks and day offsets rather than specific dates.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $week
- Week of the date.
o $day
- Offset from the first day of the week.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setISODate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setISODate(2008, 2);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 2, 7);
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create();
date_isodate_set($date, 2008, 2);
echo date_format($date, 'Y-m-d') . "
";
date_isodate_set($date, 2008, 2, 7);
echo date_format($date, 'Y-m-d') . "
";
?>
The above examples will output:
2008-01-07
2008-01-13
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setISODate(2008, 2, 7);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 2, 8);
echo $date->format('Y-m-d') . "
";
$date->setISODate(2008, 53, 7);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2008-01-13
2008-01-14
2009-01-04
Example #3
Finding the month a week is in
<?php
$date = new DateTime();
$date->setISODate(2008, 14);
echo $date->format('n');
?>
The above examples will output:
3
SEE ALSO DateTime.setDate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETISODATE(3)